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3 years ago

3/8 x 5/4 in fraction form?

Mathematics

1 answer:

Likurg_2 [28]3 years ago

7 0

Answer:

15/24

Step-by-step explanation:

Multiply the numerators by eachother and the denominators by eachother.

Simplified answer will be 5/8

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Y-x=-3 in y =mx+b form

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Answer:

that does not workk

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2 years ago

A life insurance policy cost $8.52 for every $1000 of insurance at this rate what is the cost for 20,000 worth of life insurance

Fantom [35]

Answer:

$170.40

Step-by-step explanation:

cost of policy=$8.52

Groups of $1000=20,00÷1000

=20

20,000 worth=$8.52×20

$170.40

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2 years ago

What are the coefficients in this expression? 2x +9y+(-4) Select all that apply.

zalisa [80]

A) 2 and B) 9
Coefficients are the numbers in front of a variable. The x and y wouldn’t be considered coefficients.

6 0

2 years ago

Read 2 more answers

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

If angle 1 = angle 2 and angle 2 = angle 4, what property allows you to state that angle 1 = angle 4

Gnesinka [82]

Answer:

Transitive Property

Step-by-step explanation:

You can use it for example: a = b. b = c. So a = c (Transitive Property).

6 0

3 years ago