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strojnjashka [21]
3 years ago
7

Write in the form (x+a)^2+b x^2−12x+1

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

( x - 6 )² - 35

Step-by-step explanation:

x² - 12x + 1

→ Half the middle term and place it inside the bracket

( x - 6 )² + 1

→ Square it

( x - 6 )² - 36 + 1

→ Simplify

( x - 6 )² - 35

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Which of the following statements describe the graphs of the solution set flr this inequality select two that apply
Helga [31]

Answer:

1st . The shaded region of the graph ....

2nd. The graph line is solid.

4th. The ordered pair (2 ; 5) is part of the solution set.

Step-by-step explanation:

. Because y is <u>greater</u> or equal than the line, everything above the line is part of the solution.

. Since y is greater or<u> equal</u>, the line is solid. If y was only greater the line would have been dotted.

. The pair (2 ; 5) represent the x = 2 w/ y = 5, and reading the graph you can see the at this point the lines passes through it.

7 0
3 years ago
Is the distance between -7 and -13 on a number line 6?
sattari [20]

Answer:

yes

Step-by-step explanation:

13-7=6 so that's the difference

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3 years ago
Simplify using the order of operations. (2 + 1) 3 ÷ 32 = 1 3 9 2
puteri [66]

Answer: I believe the answer is 0.1875. Must be a typo here, because...

Step-by-step explanation: parentheses first. (2+1)3%32=

After parentheses are taken out. 3x3%32= No exponents, so multiply or divide, whatever comes first.

6%32 is 0.1875

5 0
3 years ago
What is the approximate area of the shaded sector in the circle shown below
Novay_Z [31]

Answer:

please provide the diagram

3 0
2 years ago
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Complete the following exercises by applying polynomial identities to complex numbers. Factor x2 + 64. Check your work. Factor 1
Mumz [18]
x^2+64=x^2-(8i)^2=(x-8i)(x+8i)

16x^2+49=(4x)^2-(7i)^2=(4x-7i)(4x+7i)

(x+9i)^2=x^2+2x\cdot9i+(9i)^2=x^2+18xi+81i^2=x^2+18xi-81=x^2-81+18xi

(x-2i)^2=x^2-2x\cdot2i+(2i)^2=x^2-4xi+4i^2=x^2-4xi-4=x^2-4-4xi

(x+(3+5i))^2=x^2+2x(3+5i)+(3+5i)^2\\\\=x^2+6x+10xi+3^2+2\cdot3\cdot5i+(5i)^2\\\\=x^2+6x+10xi+9+30i+25i^2=x^2+6x+10xi+9+30i-25\\\\=x^2+6x+10xi+30i-16=x^2+6x-16+(10x+30)i


Used:\\i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\\\(a+b)^2=a^2+2ab+b^2
4 0
3 years ago
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