6x^2 - 8 = 4x^2 + 7x
6x^2 - 4x^2 - 7x - 8 = 0
2x^2 - 7x - 8 = 0
discriminant = b^2 - 4ac; where a = 2, b = -7 and c = -8
d = (-7)^2 - 4(2)(-8)
d = 49 + 64
d = 113
the discriminant is greater than zero, so there are two real roots
Answer:
28m
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Step-by-step explanation:
sorry if it is wrong
Hi there!
1/4 is a rational number.
Any number that can be written as a fraction is a rational number.
~ Hope this helps you ~
Step-by-step explanation:
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