Answer:
(a) Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.
(b) ![c =0.51995](https://tex.z-dn.net/?f=c%20%3D0.51995)
Step-by-step explanation:
Given
![f(x) = e^{-4x};\ [0,2]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20e%5E%7B-4x%7D%3B%5C%20%5B0%2C2%5D)
Solving (a); Does the function satisfy M.V.T on the given interval
We have:
![f(x) = e^{-4x};\ [0,2]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20e%5E%7B-4x%7D%3B%5C%20%5B0%2C2%5D)
The above function is an exponential function, and it is differentiable and continuous everywhere
Solving (b): The value of c
To do this, we use:
![f'(c) = \frac{f(b) - f(a)}{b - a}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7Bf%28b%29%20-%20f%28a%29%7D%7Bb%20-%20a%7D)
In this case:
![[a,b] = [0,2]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D%20%3D%20%5B0%2C2%5D)
So, we have:
![f'(c) = \frac{f(2) - f(0)}{2 - 0}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7Bf%282%29%20-%20f%280%29%7D%7B2%20-%200%7D)
![f'(c) = \frac{f(2) - f(0)}{2}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7Bf%282%29%20-%20f%280%29%7D%7B2%7D)
Calculate f(2) and f(0)
![f(x) = e^{-4x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20e%5E%7B-4x%7D)
So:
![f(2) = e^{-4*2} = e^{-8} = 0.00033546262](https://tex.z-dn.net/?f=f%282%29%20%3D%20e%5E%7B-4%2A2%7D%20%3D%20e%5E%7B-8%7D%20%3D%200.00033546262)
![f(0) = e^{-4*0} = e^{0} = 1](https://tex.z-dn.net/?f=f%280%29%20%3D%20e%5E%7B-4%2A0%7D%20%3D%20e%5E%7B0%7D%20%3D%201)
This gives:
![f'(c) = \frac{0.00033546262 - 1}{2}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7B0.00033546262%20-%201%7D%7B2%7D)
![f'(c) = \frac{-0.99966453738}{2}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7B-0.99966453738%7D%7B2%7D)
![f'(c) = -0.4998](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20-0.4998)
Note that:
![f'(x) = (e^{-4x})'](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%28e%5E%7B-4x%7D%29%27)
![f'(x) = -4e^{-4x}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20-4e%5E%7B-4x%7D)
This implies that:
![f'(c) = -4e^{-4c}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20-4e%5E%7B-4c%7D)
So, we have:
![f'(c) = -0.4998](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20-0.4998)
![-4e^{-4c} =-0.4998](https://tex.z-dn.net/?f=-4e%5E%7B-4c%7D%20%3D-0.4998)
Divide both sides by -4
![e^{-4c} =\frac{-0.4998}{-4}](https://tex.z-dn.net/?f=e%5E%7B-4c%7D%20%3D%5Cfrac%7B-0.4998%7D%7B-4%7D)
![e^{-4c} =0.12495](https://tex.z-dn.net/?f=e%5E%7B-4c%7D%20%3D0.12495)
Take natural logarithm of both sides
![\ln(e^{-4c}) =\ln(0.12495)](https://tex.z-dn.net/?f=%5Cln%28e%5E%7B-4c%7D%29%20%3D%5Cln%280.12495%29)
![\ln(e^{-4c}) =-2.0798](https://tex.z-dn.net/?f=%5Cln%28e%5E%7B-4c%7D%29%20%3D-2.0798)
Apply law of natural logarithm
![\ln(e^{ax}) =ax](https://tex.z-dn.net/?f=%5Cln%28e%5E%7Bax%7D%29%20%3Dax)
So:
![-4c =-2.0798](https://tex.z-dn.net/?f=-4c%20%3D-2.0798)
Solve for c
![c =\frac{-2.0798}{-4}](https://tex.z-dn.net/?f=c%20%3D%5Cfrac%7B-2.0798%7D%7B-4%7D)
When multiplying fractions, you multiply the denominators together and the numerators together.
3/8 x 4/9
(4•3)/(8•9)
12/72 = 1/6
1/6 is the final answer.
Answer:
3m + 4c
Step-by-step explanation:
Whenever a word problem says the word earn that means the slope, also known as the rate of change, will be positive. Knowing this you can determine that both the caramel and milk chocolate slopes will be positive. After figuring all that out the only thing left to do is to make the equation. You know you have two slopes, and each slope needs a variable, so you will have to look back at the question. It is given that m represents the milk chocolate and c represents the caramel. Now all you have to do is make the slope the coefficient to the corresponding variable. The milk chocolates are 3 dollars, so the 3 goes in front of the m and the caramel chocolates are 4 dollars, so teh 4 goes in front of the 4. Since both slopes are positive no negatives or minus signs will be used in the equation. Knowing all this information you can now create the expression 3m + 4c.
It is 3,998 because if u add it together it is like adding 2,000 +2,000-2
Answer: Area = 1500 feet^2
Step-by-step explanation:
Jim is enclosing a rectangular garden with 170 feet of fencing. This means the perimeter of the rectangular garden =170 feet
Let length = x
Let width = w
The length of the garden,x is 10 feet more than twice it's width, w. This means
x =10+2w---------1
Perimeter = 2x+2w =170---------2
Putting equation 1 in equation 2,
2(10+2w) +2w= 170
20 + 4w +2w = 170
6w = 170-20=150
w = 150/6
= 25feet
Put w=25 in equation 1
x =10 +2×25= 10+50=60 feet
Area = length × width = x×w
= 60×25=1500feet^2