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Slav-nsk [51]
3 years ago
9

Per has 32 cans of lead paint. If he drinks 16 , adn buys 2 times as many as he had, how many cans of paint would per have?

Mathematics
1 answer:
8090 [49]3 years ago
7 0

Answer:

the answer is 32

Step-by-step explanation:

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Jameson Middle School gives bottles of water to teachers and students who are going on a field trip. The school orders 500 bottl
Brilliant_brown [7]

Answer:

215 students

Step-by-step explanation:

500 divided by 2 = 250

250 - 35 each= 215

6 0
3 years ago
Caden biked 1 2/5 miles in 1/4 hour. If it is currently 4:00 P.M. and he has to bike 14 miles. At what time will he be finished?
Arturiano [62]

Answer:

He will finish the biking at 6:30 pm

Step-by-step explanation:

1/4 hour is same as 1/4 * 60 = 15 minutes

1 2/5 miles is same as 1.4 miles

He bikes 1.4 miles in 15 minutes

then he will bike 14 miles in 15 * 10 = 150 minutes

150

minutes is same as 2 hours 30 minutes

Adding this to 4 pm, we will get;

6:30 pm

6 0
2 years ago
Find the value of x (URGENT/GIVING BRAINLIEST)
Virty [35]

Answer:

x=25

Step-by-step explanation:

The angles 126 and (5x+1) are equal. The equation that is used is 5x+1=126.

To solve the equation, subtract 1 from both sides

5x+1-1=5x     126-1=125.

Simplify the equation. 5x=125

Divide both sides by 5.   5x/5=x     125/5=25

You would get x=25 eventually.

6 0
2 years ago
1/2 divided by 4 help meee​
sveta [45]

Answer:1/2 ÷4 = 1/2 x 1/4 = 1 /8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Kaliska is jumping rope. The vertical height of the center of her rope off the ground R(t) (in cm) as a function of time t (in s
xz_007 [3.2K]

Answer:

R (t) = 60 - 60 cos (6t)

Step-by-step explanation:

Given that:

R(t) = acos (bt) + d

at t= 0

R(0) = 0

0 = acos (0) + d

a + d = 0 ----- (1)

After \dfrac{\pi}{12} seconds it reaches a height of 60 cm from the ground.

i.e

R ( \dfrac{\pi}{12}) = 60

60 = acos (\dfrac{b \pi}{12}) +d --- (2)

Recall from the question that:

At t = 0, R(0) = 0 which is the minimum

as such it is only  when a is  negative can acos (bt ) + d can get to minimum at t= 0

Similarly; 60 × 2 = maximum

R'(t) = -ab sin (bt) =0

bt = k π

here;

k  is the integer

making t the subject of the formula, we have:

t = \dfrac{k \pi}{b}

replacing the derived equation of k into R(t) = acos (bt) + d

R (\dfrac{k \pi}{b}) = d+a cos (k \pi) = \left \{ {{a+d  \ for \ k \ odd} \atop {-a+d \ for k \ even}} \right.

Since we known a < 0 (negative)

then d-a will be maximum

d-a = 60  × 2

d-a = 120 ----- (3)

Relating to equation (1) and (3)

a = -60 and d = 60

∴ R(t) = 60 - 60 cos (bt)

Similarly;

For R ( \dfrac{\pi}{12})

R ( \dfrac{\pi}{12}) = 60 -60 \ cos (\dfrac{\pi b}{12}) =60

where ;

cos (\dfrac{\pi b}{12}) =0

Then b = 6

∴

R (t) = 60 - 60 cos (6t)

7 0
3 years ago
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