What is the area of this trapezoid?

one of the solutions to x2 − 2x − 15 = 0 is x = −3. what is the other solution? x = −5 x = −1 x = 1 x = 5

Goryan [66]

$x^{2} -2x-15=0$
P(-15)
s(-2)
$x^{2} -5x+3x-15$
=x(x-5)+3(x-5)
=(x+3)(x-5)
x=5

3 0

3 years ago

What is the discriminant of the quadratic equation 2x² - x - 3=0?

Tamiku [17]

The given quadratic equation is

$2 {x}^{2} - x - 3 = 0$

comparing with

${ax}^{2} + bx + c = 0$

We get ,

$a = 2 \\ b = - 1 \\ c = - 3$

formula :

$D = {b}^{2} - 4ac \\ \\ D = {( - 1)}^{2} - 4 \times 2 \times ( - 3) \\ \\ D = 1 - ( - 24) \\ \\D = 1 + 24 \\ \\D = 25.$

Discriminant of given quadratic equation is 25 .

option (B) 25 ✔

6 0

2 years ago

Do all number lines show only whole number

Lera25 [3.4K]

Answer:

no

Step-by-step explanation:

no because some numbers could be negative and most number lines also contain 0. whole numbers are positive, non decimal/fractional, real numbers

8 0

3 years ago

7. Which of the following can be determined from the graph below?

tatyana61 [14]

Answer:

The ordered pair (6,25) is a solution to both

$y=-\frac{5}{2}x+40$ and $y=\frac{5}{3}x+15$

Step-by-step explanation:

Part 7)

step 1

Find the equation of the line with positive slope

take the points (0,15) and (9,30)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{30-15}{9-0}$

$m=\frac{15}{9}$

simplify

$m=\frac{5}{3}$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=\frac{5}{3}$

$b=15$

substitute

$y=\frac{5}{3}x+15$

step 2

Find the equation of the line with negative slope

take the points (0,40) and (8,20)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{20-40}{8-0}$

$m=-\frac{20}{8}$

simplify

$m=-\frac{5}{2}$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=-\frac{5}{2}$

$b=40$

substitute

$y=-\frac{5}{2}x+40$

step 3

Find the solution of the system

we know that

The solution of the system of equations is the intersection point both graphs

The intersection point is (6,25) ----> see the graph

therefore

The ordered pair (6,25) is a solution to both $y=-\frac{5}{2}x+40$ and

$y=\frac{5}{3}x+15$

7 0

3 years ago

A canoe in still water travels at a rate of 12 miles per hour. The current today is traveling at a rate of 2 miles per hour. If

VARVARA [1.3K]

Answer:

It’s 60miles

Step-by-step explanation:

We assume the trip is "d" miles and that the "extra hour" refers to the additional time that a current of 2 mph would add. That is, we assume the reference time is for a current of 0 mph.

The time with no current is ...

time1 = distance/speed

time1 = d/12 . . . . hours

With a current of 2 mph in the opposite direction, the time is ...

time2 = d/(12 -2) = d/10

The second time is 1 hour longer than the first, so we have ...

time2 = 1 + time1

d/10 = 1 + d/12

6d = 60 + 5d . . . . multiply by 60

d = 60 . . . . . . . . . subtract 5d

The one-way distance is 60 miles.

7 0

2 years ago

What is the area of this trapezoid?​

What is the area of this trapezoid?