Answer:
55.5 B
Step-by-step explanation:
We have the following points of data
48, 49, 50, 51, 54, 55, 56, 58, 60, 62, 63, 63
The median is the data point in the middle (when listed in order)
If we find the middle number we'll see that it's between 55 and 56. When this is the case you find the average of the two numbers (add them and divide by 2)
(55+56)/2=55.5
Double is double, so you can solve
.. 2 = 1*e^(.08t)
and get the correct value of t.
Taking logs,
.. ln(2) = .08t
.. ln(2)/.08 = t ≈ 8.7 . . . . years
Answer:
56
Step-by-step explanation:
Answer:
4 minutes
Step-by-step explanation:
Let the time taken for them to have the same number of strawberries be x minutes.
<u>Initially</u>
Ruby: 10 strawberries
Sapphire: 30 strawberries
<u>After x minutes</u>
Ruby: (10 +3x) strawberries
Sapphire: (30 -2x) strawberries
Since we let x minutes be the amount of time that has passed when they have the same amount of strawberries,
10 +3x= 30 -2x
Bring all x terms to one side, constant to the other:
3x +2x= 30 -10
Simplify:
5x= 20
Divide both sides by 5:
x= 20 ÷5
x= 4
∴ It will take 4 minutes.
Answer:
AUB = {E1, E2, E4, E6, E7}
Step-by-step explanation:
Since we are to look for the union of the two sets, therefore we combine all the sample points that are contained in A and B without repeating any sample even if such sample occur in both sets. For example, E4 occurs in event A and B and as such will only be repeated once in the union of the two events.
AUB = {E1, E2, E4, E6, E7}
Note that the way you arrange does not matter as well.
I hope you find this solution useful?
