1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lidiya [134]
3 years ago
15

Determine the solution x^2 - 3x -28 ≥ 0

Mathematics
2 answers:
KengaRu [80]3 years ago
8 0

Answer:

(Infinity)],-4 or 7, ( Infinity)



IgorC [24]3 years ago
4 0

x^2 - 3x -28 ≥ 0

factor

(x-7) (x+4) ≥ 0

x=7  x=-4

we have three regions where the answers can lie

x<-4  between -4 and 7  and x>7

pick a point and see if it works

x=-10

(-10-7) (-10+4) ≥ 0

negative * negative  is greater than 0 so this is a solution   x< -4

x=0

(0-7) (+4) ≥ 0

negative * positive  is less than 0 so this is  not a solution  

x=10

(10-7) (10+4) ≥ 0

positive * positive is greater than 0 so this is a solution   x>7

We have two regions that work

x<-4 and x>7




You might be interested in
Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m
ch4aika [34]

Answer:

\ln x+\frac{1}{3}\ln (x^2+1)

Step-by-step explanation:

Consider the given expression is

\ln (x\sqrt[3]{x^2+1})

We need to rewrite the expression as a sum,difference,or multiple of logarithms.

\ln (x(x^2+1)^{\frac{1}{3}})        [\because \sqrt[n]{x}=x^{\frac{1}{n}}]

Using the properties of logarithm we get

\ln x+\ln (x^2+1)^{\frac{1}{3}}         [\because \ln (ab)=\ln a+\ln b]

\ln x+\frac{1}{3}\ln (x^2+1)        [\because \ln (a^b)=b\ln a]

Therefore, the simplified form of the given expression is \ln x+\frac{1}{3}\ln (x^2+1).

6 0
3 years ago
N n N n N n N n N n n N N Suppose that you were to draw a random sample of one letter from the set of letters above. Two possibl
kvv77 [185]

Answer:

10/13 = 76.92%

Step-by-step explanation:

The question is missing some information because the underline is missing.

If we make table based on if the letter upper case (A) or lower case(a), and if the letter underlined(B) vs not underlined(b) the data will be:

             A          a

B           4           3         7

b           3           3         6

total      7          6

There are total of 13 letter there. The calculation will be:

P(A or B) = P(A) + P (B) - P(A and B) = (7 + 7 -4) / 13= 10/13 = 76.92%

4 0
3 years ago
I will give brainliest. Combine the like terms to create an equivalent expression: −5j+(−2j)+3
neonofarm [45]

Answer:

-7j +3

Step-by-step explanation:

-5j -2j +3

-7j +3

like terms are combined. combine the js

8 0
3 years ago
Read 2 more answers
Can I get help on this question or an example? I would really appreciate it.
gulaghasi [49]

Answer:

B = 0.95m + 29.95

Step-by-step explanation:

this is really y = mx + b

m is a rate, 0.95 per mile

b is the y-intercept, or the price you pay no matter what, 29.95

8 0
2 years ago
Please help asap!! will give brainlist :)
Naddik [55]

Yo sup??

Area of trapezium=1/2*(sum of opposite sides)*(height of trapezium)

=1/2*(12.5+17.5)*6

=1/2*30*6

=90 cm²

Therefore the correct answer is option A

Hope this helps.

8 0
3 years ago
Read 2 more answers
Other questions:
  • What percent of 450 is 9
    13·2 answers
  • X squared + 9x + 14=0<br><img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20%2B%209x%20%2B%2014" id="TexFormula1" title
    13·1 answer
  • Ok I’m sorry but this is the last question. I need help please
    12·1 answer
  • Is this pattern a net for the three-dimensional figure?
    11·2 answers
  • How do you find the surface area and volume of this?
    14·1 answer
  • 1. Mrs. Verner's class has
    9·1 answer
  • Help!! Will mark brainliest
    5·2 answers
  • Are 5/8 and 2/3 equivalent
    6·2 answers
  • Which expression is equivalent to x2-16 ?
    11·1 answer
  • Radio waves have the longest wavelength. If a particular radio wave is 1km long with a speed of
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!