Let quarters = q and
Dimes = d
We have 741 coins total so q + d = 741
Since quarters are 25 cents and Dimes are 10 cents then
25q + 10d = 10725 cents
Now we have 2 equations that we can solve using addition or substitution.
Using addition, first multiply the first equation by -10
-10 (q+d) = 741 (-10)
-10q - 10d = -7410
Now add the equations together
(-10q -10d = -7410)
+ (25q + 10d =10725)
________________
15q = 3315
q = 3315 / 15
q = 221
this is the number of quarters
Now plug this back into the original equation
q + d = 741
221 + d = 741
d = 741 - 221
d = 520
There are 520 dimes
Answer:
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Answer:
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Answer:
8n - (2n + 11 - 54) =
Step-by-step explanation:
6n + 43, I used a calculator !
