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Aliun [14]
2 years ago
12

Helpppppppppp!!!!! someone help me!!

Mathematics
1 answer:
lord [1]2 years ago
7 0

Answer:

why? Are you dying?

Step-by-step explanation:

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Glenn, the owner of a hardware store, originally paid $54.60 for 15 tool sets. At his year-end clearance sale, he sold the last
Sonja [21]

The amount of money he lose on the last tool set is: $30.60.

<h3>Amount lose</h3>

Using this formula

Amount lose=Original amount paid -Selling price

Where:

Original amount paid=$54.60

Selling price=$24.00

Let plug in the formula

Amount lose=$54.60-$24.00

Amount lose=$30.60

Therefore the amount of money he lose on the last tool set is: $30.60.

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3 0
2 years ago
Please help I can’t figure this question out
densk [106]
I think the answer would be 7/50
8 0
2 years ago
Read 2 more answers
Are the graphs of the lines in the pair parallel? Explain. y=2\3x-17 4x-6y=-7
Papessa [141]
<span>y=2\3x-17and  4x-6y=-7 implies  - 6y= - 4x -7, and then y= (-4/-6)x +7/6 and so 
y=2/3x+7/6

but when we have y=ax+b and y=a'x+b', the two lines are parallels if a=a', in our case 2/3=2/3 the lines are parallel
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6 0
3 years ago
Select the correct word to describe the function. the equation y = startfraction 5 x cubed over 8 endfraction represents functio
balandron [24]

The functions and their descriptions are:

  • Polynomial: y = \frac{5x^3}{8} and y = 5x^3 + 8
  • Logarithm: y = 6 + 0.25\ln(x)
  • Exponential y = \frac{18}{1 + 6e^{-0.25x}}

<h3>How to describe the functions?</h3>

The functions are given as:

y = \frac{5x^3}{8}

y = 6 + 0.25\ln(x)

y = \frac{18}{1 + 6e^{-0.25x}}

y = 5x^3 + 8

The functions would be described based on the type of function they represent.

Functions that use the "ln" keyword are logarithmic functions, while functions that use the "e" keyword are exponential functions.

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7 0
2 years ago
The sum of the first terms of an Arithmetic progression (Ap) is 130.if the fifth term is 3times,the first term,find the (a)commo
Nadusha1986 [10]

Answer:

For part a)

130 = 10/2[2a+(10-1)d]

Simplify, u get

2a + 9d = 26.................(1)

Also U5 = a + (5-1)d = 3a

Simplify, u get

a= 2d...................(2)

Substituting for a in equation 1,

2(2d)+9d= 26

Solving for d, we get

d = 2

In part b) substituting for d in equation 2 to get the first term

a = 2(2) = 4

Part c) the no. of terms required can be obtained by solving

28 = 4+(n-1)2

n = 13

5 0
3 years ago
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