The sum of the first terms of an Arithmetic progression (Ap) is 130.if the fifth term is 3times,the first term,find the (a)commo
n difference (b)first term (c)number of terms of the Ap if the last term is 28.
1 answer:
Answer:
For part a)
130 = 10/2[2a+(10-1)d]
Simplify, u get
2a + 9d = 26.................(1)
Also U5 = a + (5-1)d = 3a
Simplify, u get
a= 2d...................(2)
Substituting for a in equation 1,
2(2d)+9d= 26
Solving for d, we get
d = 2
In part b) substituting for d in equation 2 to get the first term
a = 2(2) = 4
Part c) the no. of terms required can be obtained by solving
28 = 4+(n-1)2
n = 13
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Answer:
M=120⁰
Step-by-step explanation:
Assuming in isoscele trapezoid:
M+H=180
M+60=180
M=120⁰