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mihalych1998 [28]
2 years ago
14

Glenn, the owner of a hardware store, originally paid $54.60 for 15 tool sets. At his year-end clearance sale, he sold the last

tool set for 24.00 How much money did he lose on the last tool set.
Mathematics
1 answer:
Sonja [21]2 years ago
3 0

The amount of money he lose on the last tool set is: $30.60.

<h3>Amount lose</h3>

Using this formula

Amount lose=Original amount paid -Selling price

Where:

Original amount paid=$54.60

Selling price=$24.00

Let plug in the formula

Amount lose=$54.60-$24.00

Amount lose=$30.60

Therefore the amount of money he lose on the last tool set is: $30.60.

Learn more about amount lose here:brainly.com/question/11872053

#SPJ1

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Please help with this math question
nika2105 [10]
263.27 m^2

rectangle : 15 x 10 = 150 m^2
the half circle at the top has a diameter of 6m. therefore, it’s radius is 3m. if it is cut in half, the part removed from the triangle height is 3m. therefore, the height of the triangle is 35 -15 = 20; 20 - 3 = 17. the height of the triangle is 17. the triangle area formula is a = 1/2(bh).
a = 1/2 (10)(17)
a = 1/2 (170)
a = 85 m^2
the circle would be a = πr^2 but divided by 2 bc it’s a half circle
a = π(3)^2
a = π9
a = 28.27 m^2
150 + 85 + 28.27 = 263.27 m^2
3 0
3 years ago
A ____ compares two numbers by division?
barxatty [35]
Usually a ratio will compare two numbers by division

4 0
3 years ago
14x + 5y = -6<br> Slope intercept form
andrew11 [14]

Answer:

y=-2.8x-1.2

Step-by-step explanation:

5y=-14x-6

y=-14/5x-6/5

y=-2.8x-1.2

7 0
3 years ago
Read 2 more answers
Round 202.366 to the nearest hundredth
GuDViN [60]
Hello there,

202.366 to the nearest hundredth would be 202.37.

So what I did was I look at the 366 in the problem.

We want to round the to the nearest hundredth.

So what we would do it notice how the 66 in over 50.

The rule is if it's over 50, we round it to the nearest.

So your answer would be 202.37.

Hope this helps.

~Jurgen
3 0
3 years ago
A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ
ElenaW [278]

Answer:

n(S\cap F \cap R)=7

Step-by-step explanation:

The Universal Set, n(U)=2092

n(S)=1232\\n(F)=879\\n(R)=114

n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14

Let the number who take all three subjects, n(S\cap F \cap R)=x

Note that in the Venn Diagram, we have subtracted n(S\cap F \cap R)=x from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, n(S\cap F \cap R)=7

3 0
3 years ago
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