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Shalnov [3]
2 years ago
14

Which of the following statements must be true based on the diagram below select all that apply

Mathematics
1 answer:
ipn [44]2 years ago
3 0

Answer:

all are true other than NONE OF THE ABOVE

Step-by-step explanation:

Hope this helps. let me know if any questions.

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Which graph represents y=x-2
NemiM [27]

Answer:

Graph B

Step-by-step explanation:

7 0
2 years ago
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R/16 + 6 = 7 pLEASE HELP WITHIN A HOUR OR TWO
cestrela7 [59]

Solution:

<u>Simplify the equation and solve for r.</u>

  • r/16 + 6 = 7
  • => r/16 = 7 - 6
  • => r/16 = 1
  • => r = 16

The value of r is 16.

<u>Check:</u>

  • r/16 + 6 = 7
  • => 16/16 + 6 = 7
  • => 1 + 6 = 7
  • => 7 = 7 (Proved correct)
7 0
2 years ago
Read 2 more answers
I need help fast !!
AysviL [449]
<h2>Answer:</h2>

Luke does a work of 308Nm

<h2>Step-by-step explanation:</h2>

If we have a constant force \vec{F} that acts on a body in the same direction as the displacement \vec{s}, then the work W is defined as the product of the force magnitude F and the displacement magnitude s. In other words:

W=Fs, which is valid for a constant force in direction of straight-line displacement.

In this problem:

F=22N \\ \\ s=14m

Therefore:

W=22\times 14 \\ \\ \boxed{W=308Nm}

3 0
3 years ago
Describe and correct the error in finding the solution.​
yaroslaw [1]
The error is in step 2. if you are performing an operation on one side of the equation, it must be performed on the entire expression. you can’t only divide by 2 on one term, you must do it to everything in the equation. instead, you could add 6 to both sides first, giving you 2x = -4. Then you can divide by 2 on both sides. the answer is -2.
6 0
3 years ago
A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 1:4.
schepotkina [342]

Let point C has coordinates (x_C,y_C). Consider vectors

\overrightarrow{AB}=(x_B-x_A,y_B-y_A)=(8-9,6-9)=(-1,-3),\\ \\\overrightarrow{BC}=(x_C-x_B,y_C-y_B)=(x_C-8,y_C-6).

Since the ratio AB to BC is 1:4, you have that

\dfrac{-1}{x_C-8}=\dfrac{1}{4}\quad \text{and}\quad \dfrac{-3}{y_C-6}=\dfrac{1}{4}.

Find x_C and y_C:

x_C-8=-4,\\ \\x_C=-4+8=4,\\ \\y_C-6=-3\cdot 4=-12,\\ \\y_C=-12+6=-6.

Answer: C(4,-6)

7 0
2 years ago
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