Your answer would be -15.41. If you ever need any other kind of help, just ask me.
Explanation:
Unclear question. But I inferred this to be clear rendering of your question;
1) It is considered a circle and a certain point. The expressions dot inside the circle, dot on circle, or dot outside the text describe the position of a dot relative to a circle. In figure 2 are drawn: a circle C of center O, points on the circle, points outside the circle and points inside the circle. a) Name the points inside the circle; b) Name the points that belong to the circle; c) Name the points outside the circle.
2) Consider any point P and a circle C of center O and radius r. Compare the distance OP with the radius of the circle if: a) The point is inside the circle; b) The point is on the circle; c) The point is outside the circle.
Answer:
22 pounds
Step-by-step explanation:
c+s=52, c = 52-s
3c+5s=200
3(52-s) +5s = 200
156 - 3s +5s = 200
5s-3s = 200-156
2s = 44
Shrimp = 44/2 = 22 pounds
By definition of absolute value, you have
or more simply,
On their own, each piece is differentiable over their respective domains, except at the point where they split off.
For <em>x</em> > -1, we have
(<em>x</em> + 1)<em>'</em> = 1
while for <em>x</em> < -1,
(-<em>x</em> - 1)<em>'</em> = -1
More concisely,
Note the strict inequalities in the definition of <em>f '(x)</em>.
In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:
All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.
Addition,subtraction,and multiplication
