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MrRissso [65]
2 years ago
15

Given f(x)=3x^3+2x+k and x+1 is a factor of f(x) then what is the value of k

Mathematics
1 answer:
yaroslaw [1]2 years ago
3 0

Answer:

k = 5

Step-by-step explanation:

Given that (x + 1) is a factor of f(x) then f(- 1) = 0

f(- 1) = 3(- 1)³ + 2(- 1) + k

      = 3(- 1) - 2 + k

     = - 3 - 2 + k

    = - 5 + k

Then - 5 + k = 0 ( add 5 to both sides )

k = 5

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7 0
2 years ago
Roderick is counting the change on his dresser. he has twice as many pennies as he does dimes. he has twice the amount of dimes
melamori03 [73]
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the temperature dropped 3°c every hour for 5 hours. write an integer that represents the change in temperature
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7 0
3 years ago
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A standard number cube has 6 sides labeled 1 to 6. apu rolls a standard number cube 30 times. How many times can
Leviafan [203]

Answer:

The expected value of rolling a 5 or 6 is 10.

Step-by-step explanation:

The sample space of rolling a standard number cube is:

S = {1, 2, 3, 4, 5 and 6}

The cube is standard, this implies that each side has an equal probability of landing face-up.

So, the probability of all the six outcomes is same, i.e. \frac{1}{6}.

Now it is provided that Apu rolls the cube <em>n</em> = 30 times.

Let the random variable <em>X</em> represent the value on the face of cube.

The event of rolling a 5 and rolling a 6 are mutually exclusive, i.e. they cannot occur together.

So, P (X = 5 and X = 6) = 0.

Compute the probability of getting a 5 or 6 as follows:

P (X = 5 or X = 6) = P (X = 5) + P (X = 6) - P (X = 5 and X = 6)

                            = P (X = 5) + P (X = 6)

                            =\frac{1}{6}+\frac{1}{6}\\\\=\frac{2}{6}\\\\=\frac{1}{3}

Compute the expected value of rolling a 5 or 6 as follows:

E(X = 5\ \text{or}\ X = 6)=n\times P(X = 5\ \text{or}\ X = 6)

                               =30\times \frac{1}{3}\\\\=10

Thus, the expected value of rolling a 5 or 6 is 10.

8 0
3 years ago
What is 240÷6? to find how man grapes Ally ate.
s344n2d4d5 [400]

240 / 6

40

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2 years ago
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