Answer:
We know length of one quarter of a circle = 2πr/4 = πr/2
So here we can make the equation for to find thr value of radius r
length of one quarter given = 25 cm
so πr/2 = 25 cm
=> πr = 50 cm
=> r = 50/π cm
So the entire circumference of circle =
2πr
= 2 π 50/π cm
= 100π/π cm (ans)
Here we dont substitute the value of π due to represent the answer in terms of pi.
Hope it helps you
Oh boy, here we go again
First we must convert 1 2/3 to an improper fraction. By doing this, we get 5/3 (3/3 + 2/3)
So now we have 273 / 5/3
To divide this easier we can do something that when I learned it was called (keep, change, flip) which basically means keep the first fraction, change the sign from division to multiplication, and flip the second fraction
This now turns into: 273/1 * 3/5
Combine 273 and 3/5
273⋅3/5
Multiply 273
by 3
819/5
is your answer
Answer:
The leading coefficient is 1 and the linear term coefficient is an even number
Step-by-step explanation:
Leading coefficient must be one for the application of completing square method. If the completing square is not one than we must apply other methods like Ac method, quadratic formula to solve the equation. To solve the equation with completing square the numerical value must be on other side of the equation. In this method we multiply linear term’s coefficient with one-half and square it therefore, completing square is suitable method for the equation having leading coefficient is 1 and linear coefficient is even.
Use the formula
n(n-1)/2
which is the total number of connections between n points
So,
4(3)/2 = 6
the answer is option C.
Hope this helps
Answer:
39.50
42.50
Step-by-step explanation:
Age of the 2 men = sum of the ages of the 6 men - sum of the ages of the 4 men
Average = sum of ages / total number of men
35 = sum of ages / 6
sum of ages = 35 x6 = 210
32 = sum of ages / 4
32 x 4 = sum of ages
128
210 - 128 = 82
age of the younger man = x
age of the older man = 3 + x
x + 3 + x = 82
2x + 3 = 82
2x = 82 - 3
2x = 79
x = 79/2 = 39.5
older man = 39.5 + 3 = 42.50
