Answer:
Step-by-step explanation:
We are given that
y(0)=0
y'(0)=1
By comparing with
We get
q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=
Is there a picture to go with it
Answer:
Refer to the picture that given
Step-by-step explanation:
:))
Answer:
a. Between 6.7 and 6.9
Step-by-step explanation:
√(25 + 3 + 17) = √45
6² = 36
7² = 49
√45 is close to 7 but slightly under. So best answer is A.
Answer:
378x³⁰²
Step-by-step explanation:
378x378x378x378x378x378x378x378x378
=378*x^378*x^378*x^378*x^378*x^378*x^378*x^378*x^378
=378*x3024
=378x³⁰²
Hope this helps
