9514 1404 393
Answer:
5/2
Step-by-step explanation:
The rules of exponents apply.
a^-b = 1/a^b
(a^b)^c = a^(bc)
a^(1/2) = √a
__
Alternatively, ...
Exponential equation are functions defined by
The equation that could represent Rainey graph must take the form
<h3>How to determine the equation</h3>
An exponential equation is represented as:
Where:
- a represents the initial value
- b represents the rate
The initial value (a) is 15.
So, the equation becomes
The graph is not given;
So, the equation cannot be determined.
Assume that the rate is 2.
Then the function would be:
Read more about exponential functions at:
brainly.com/question/11464095
Answer: just read
Step-by-step explanation:
So first you plot the points, then calculate how many units it takes from the point that is Sean’s house to his School. Show your work on that by drawing out your skip counting. Then you plot the rest of the points and fpro this calculation: the distance from Sean’s house to his school+ from his school to the grocery store. Then you calculate the distance (in units! ! ! Which means one box is one unit) : distance from Sean’s house to the school+ from school to the commmunity center. Then two calculations you made above you compare. So whichever one is greater is your answer for part b.
Answer:
39 degrees
Step-by-step explanation:
Add: 39+54+48=141
180 (degrees of a straight angle) minus 141=39
39 degrees
Hope I helped!! :)
Brainliest?!?!
Stay safe and have a good day/night/afternoon!!!
9514 1404 393
Answer:
31.243 units
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.
Sin = Opposite/Hypotenuse
sin(30°) = BE/100
BE = 100·sin(30°)
Then ...
Tan = Opposite/Adjacent
tan(58°) = BE/x
x = BE/tan(58°) = 100·sin(30°)/tan(58°)
x ≈ 31.243 . . . . units
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<em>Comment on the figure</em>
The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.