Your question is confusing, please make it more detailed or provide a picture and ill Edit this answer.
Thank you!
We found a counterexample, so the statement is false.
<h3>
Is the statement true?</h3>
Let's use the matrix:
![\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-2%260%260%260%5C%5C0%261%260%260%5C%5C0%260%261%260%5C%5C%200%260%260%261%20%5Cend%7Barray%7D%5Cright%5D)
This is a 4x4 matrix with determinant equal to -2.
The inverse matrix is:
![\left[\begin{array}{cccc}1/2&0&0&0\\0&-1&0&0\\0&0&-1&0\\ 0&0&0&-1 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%2F2%260%260%260%5C%5C0%26-1%260%260%5C%5C0%260%26-1%260%5C%5C%200%260%260%26-1%20%5Cend%7Barray%7D%5Cright%5D)
If we multiply it by 2, we get:
![\left[\begin{array}{cccc}1&0&0&0\\0&-2&0&0\\0&0&-2&0\\ 0&0&0&-2 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%260%5C%5C0%26-2%260%260%5C%5C0%260%26-2%260%5C%5C%200%260%260%26-2%20%5Cend%7Barray%7D%5Cright%5D)
The adjoint of that is the original matrix, actually:
![\left[\begin{array}{cccc}-2&0&0&0\\0&1&0&0\\0&0&1&0\\ 0&0&0&1 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-2%260%260%260%5C%5C0%261%260%260%5C%5C0%260%261%260%5C%5C%200%260%260%261%20%5Cend%7Barray%7D%5Cright%5D)
Which we already know, has a determinant of -2.
So the statement is false, as we found a counterexample.
If you want to learn more about matrices:
brainly.com/question/11989522
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Answer:
ask your teacher it would be good for you and also teachers give u good thing about that okay but i can't help you sorry.
Step-by-step explanation:
1) 6÷0.2 = 30
If 6/2=3 then 6/0.2=30 as the decimal place shifts one place.
2)8÷0.1 = 80
8/1=8 so shift the decimal place over once to make 80.
3)9÷0.3 = 30
9/3=3 so shift the decimal place over once to get 30.
4)4÷0.04 = 100
4/4=1 so shift the decimal place over twice to get 100.
5)7÷0.002 = 3500
7/2=3.5 so shift the decimal place over three times to get 3500
6)0.718÷0.2 = 3.59
718/2=359 so shift the decimal over three places for the 0.718 and then back over once for the 0.2
7)0.0141÷0.003 = 4.7
141/3=47 so shift the decimal over our times for the 0.0141 and then back over three times for the 0.003
8)0.24÷0.012 = 20
24/12=2 so shift the decimal point over once twice for 0.24 then back over three times for 0.012
9)1.625÷0.0013 = 1250
1625/13=125 so shift the decimal point over three times for the 1.625 and then back four times for the 0.0013
10)47.1÷0.15 = 314
471/15=31.4 so shift the decimal point over once for the 47.1 and then back over twice for the 0.15.
Hope this helps :)
Answer:
y-5 = -6(x+3) OR y = -6x-13
Step-by-step explanation:
Let's use slope-intercept form to solve this problem.
Slope intercept form is the following:
y-y1 = m(x-x1)
x1 and y1 are given by the point in the problem.
x1 = -3, y1 = 5.
m is given by the equation in the problem. Lines that are parallel have the same slope. Thus,
m = -6.
If we plug these values into the equation for slope intercept form, we get the following:
y-5 = -6(x-(-3)) which becomes y-5 = -6(x+3)
This is an acceptable answer to the problem. However, point-slope form is also a way it can be written.
y-5 = -6x-18
y = -6x-13