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Elena-2011 [213]
3 years ago
11

Fill in the blank with the correct word.

Mathematics
1 answer:
WITCHER [35]3 years ago
4 0
………………………………………Right
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Select the correct answer.A town park has two paths leading to the playground. One path is 2 miles from the road and the other p
damaskus [11]

Given:

There are given that the two paths and one path are 2 miles from the road.

Explanation:

Suppose the distance from the playground to the road is x.

To find the value x, we need to use the cos function;

So,

From the cos function in the given right angle triangle:

cos50^{\circ}=\frac{x}{2}

Then,

\begin{gathered} cos50^{\operatorname{\circ}}=\frac{x}{2} \\ 0.64=\frac{x}{2} \end{gathered}

Then,

\begin{gathered} 0.64=\frac{x}{2} \\ x=0.64\times2 \\ x=1.28 \\ x=1.3mi \end{gathered}

Final answer:

Hence, the correct option C.

4 0
1 year ago
(19 points) please please help me thanks
yawa3891 [41]

Answer:

1.335 Kilograms

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What are the missing parts that correctly complete the proof?
Pepsi [2]

Answer:

1. point p is on the perpendicular bisector of AB¯¯¯¯¯- given

2. AXP≅BXP. definition of bisector

3. ∠PXA and ∠PXB are right angles. definition of perpendicular

4. ∠PXA≅ ∠PXB. All right angles are congruent.

5.PX¯¯¯¯¯≅PX¯¯¯¯¯ ​ Reflexive Property of Congruence

6.AXP≅AXQ. SAS Congruence Postulate

7.AX¯¯¯¯¯≅BX¯¯¯¯¯

8.Point P is equidistant from the endpoints of AB¯¯¯¯¯. Definition of equidistant

Step-by-step explanation:

3 0
3 years ago
Liza bought 5/8 pound of trail mix. She gives 2/8 pound of trail mix to michael. How much trail mix does liza have left?
cricket20 [7]
Liza has 3/8 pounds of trail mix left. I just subtracted 5/8-2/8 since they have common denominators you keep the denominator the same and just subtract the numerators, so 5/8-2/8= 3/8 pounds.
8 0
3 years ago
The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
ankoles [38]

Answer:

     2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

  T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

  D_x=T_x\sqrt{T_x}

The mean distance of planet Y can be found using the given relation ...

  T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x

The mean distance of planet Y is increased from that of planet X by the factor ...

  2√2

8 0
2 years ago
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