1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STatiana [176]
3 years ago
14

Helpp plsss!!! :(((((

Mathematics
2 answers:
stira [4]3 years ago
7 0

Step-by-step explanation:

HERE IS UR ANSWER

I HOPE IT HELPS YOU

Rudik [331]3 years ago
3 0

Sign ">" is the correct option.

<em><u>Proof:</u></em><em><u>-</u></em>

Let,

<h2>Case 1:-</h2>

12 \div 4 + 13

3 + 13

16

<h2>Case 2:-</h2>

2 + 22 \div 2

2 \div 11

13

So, Case 1 = 16, Case 2 = 13.

While considering both answers, the truth is:-

Case 1 > Case 2

→ 16 > 13

→ 12÷4+3 <u>></u> 2+22÷2

<em>Hope</em><em> it</em><em> </em><em>helps</em><em> </em><em>you.</em>

<em>Answe</em><em>r</em><em>e</em><em>d</em><em> </em><em>by </em><em>Benjemin</em><em> </em>☺️

Pls mark brainliest if it helps you.

✅

You might be interested in
Do Dollar markdowns represent price increases to the original selling price.
e-lub [12.9K]
No they don't wahwah
7 0
4 years ago
Read 2 more answers
Find the base of a parallelogram with a slant height of 7cm and an perimeter of 63 cm2
vlada-n [284]

Base of parallelogram b = 24.5 cm

Step-by-step explanation:

We are given:

Perimeter =P= 63 cm^2

Slant Height =a= 7 cm

Base of Parallelogram =b= ?

The formula used is:

Perimeter = 2(a+b)

where a is height and b is base

Putting values:

Perimeter = 2(a+b)\\63=2(7+b)\\63=14+2b\\2b=63-14\\2b=49\\b=\frac{49}{2}\\b=24.5

So, Base of parallelogram b = 24.5 cm

Keywords: Perimeter of Parallelogram

Learn more about Perimeter of Parallelogram at:

  • brainly.com/question/6594923
  • brainly.com/question/1822996
  • brainly.com/question/6594923

#learnwithBrainly

5 0
4 years ago
A books thickness in 31 millimeters what is the thickness in centimeters
Natasha2012 [34]
\bf \begin{array}{ccllll}&#10;cm&mm\\&#10;\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;1&10\\&#10;x&31&#10;\end{array}\implies \cfrac{1}{x}=\cfrac{10}{31}

solve for "x"
6 0
3 years ago
Help me plzzzzzz 100% and ill give a a Brainlist
OLga [1]
Idk 60................
7 0
3 years ago
Read 2 more answers
An English professor determined the mean of her final exam scores to be 78 with a standard deviation of 6.3. Find the minimum an
Morgarella [4.7K]

Solution: We are given:

Mean =78, Standard-deviation =6.3

We know that a usual values of the test scores falls within 2 standard deviation from the mean.

Therefore, the minimum usual test score is:

Mean - 2 Standard-deviation

78-2 \times 6.3

78-12.6

65.4

The maximum usual test score is:

Mean + 2 Standard-deviation

78+2 \times 6.3

78+12.6

90.6

Therefore, the minimum and maximum “usual” values of the test scores are:

65.4 and 90.6

5 0
3 years ago
Read 3 more answers
Other questions:
  • Amelia earns $540 in a biweekly pay period. She has one withholding allowance. The withholding allowance exempts $3,800 annually
    5·1 answer
  • Which property is being used?<br> If HJ+5=20, then HJ=15.
    7·1 answer
  • I think its 2, 150 but just making sure.
    13·1 answer
  • Diviseur de 63 et 67
    14·2 answers
  • In the triangle pictured, let A, B, C be the angles at the three vertices, and let a,b,c be the sides opposite those angles. Acc
    13·1 answer
  • Choose the graph which represents the solution to the inequality. 12x + 4 ≤ -8
    9·1 answer
  • For leaving school to visit Mexico Levant traded 270 American dollars and received 3000 Mexican pesos. When he returned from Mex
    8·1 answer
  • What is the correct answer of 4 3/4 + 2 5/6
    6·1 answer
  • Need help immediately <br> What is the equation of the line shown?
    11·1 answer
  • Evaluate b<br> -<br> (6)<br> + c where b = 2 and c<br> 7<br> 4
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!