Answer:
hmmm I think u need to talk to ur teacher
let's notice the tickmarks on the left and right sides, meaning those two sides are twins, and therefore equal, so the perimeter is simply 2.5+2.5+3.5+2.5 = 11 ft.
the trapezoid has an altitude/height of 2 ft, thus
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=2.5\\ b=3.5\\ h=2 \end{cases}\implies A=\cfrac{2(2.5+3.5)}{2}\implies A=6](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2.5%5C%5C%20b%3D3.5%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B2%282.5%2B3.5%29%7D%7B2%7D%5Cimplies%20A%3D6)
Answer:
8 years is around 2,920 days
Step-by-step explanation:
Answer:
x=6
Step-by-step explanation:
multiply 7 by x and 7 by -4. You get 7x-28=14, add 28 to 14, which is 42. So 7x=42, then divide 7 on both sides, and you get x=6.
The correct answer will be option C. Mode.
Mode is the most frequently occurring value of the data. From the above line plot we can see that the most frequently occurring value is 3. Even if 10 is removed from the line plot, 3 will still be the most frequently occurring value and will be the mode of the data. Thus removing 10 does not changes the mode of the data at all.
The mean will obviously be changed. The range is difference of maximum and minimum value. 10 was initially the maximum value. If 10 is removed, the maximum value will change and so does the Range of the data. Removing 10 changes the total number of data values, so the position of median also changes which changes the value of Median.
Therefore, the correct answer to this question is option C