1.) (-3,-2)
2.) 8.4m^3
3.) 37.7m^3
Step-by-step explanation:
It is not a solution because the point falls outside the shaded region, if you were to plugin the point it would return a false statement
If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)
The total volume of the ball will be;
= Total volume - Volume of hollow part
= 4/3πr³ - 4/3πr³
= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³
= 4 × 3.14 × 9 - 4/3 × 3.14 × 8
= 113.04 - 33.52
= 79.52
If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;
= 79.52 × 3.25
= 258.44 g
Now, if there are 8 spheres in one box, the weight if box will be;
= 258.44 × 8
= 2,067.52 g
_____________________________
Ahh! Finally done with this, if you have any doubt just do ask me :)
Answer:
0.918 is the probability that the sample average sediment density is at most 3.00
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 2.80
Standard Deviation, σ = 0.85
Sample size,n = 35
We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling:
P(sample average sediment density is at most 3.00)
Calculation the value from standard normal z table, we have,
0.918 is the probability that the sample average sediment density is at most 3.00
Answer:
Change your greater than to less than
Step-by-step explanation:
The -1 1/4 is farther away from 0 than -1, which means it's less than -1.
