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Pavlova-9 [17]
3 years ago
8

Please help asap :( This is my "Final grade" My Teacher wants a full explanation included ! on how i got the answer. )

Mathematics
1 answer:
Mrac [35]3 years ago
3 0

If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)

The total volume of the ball will be;

= Total volume - Volume of hollow part

= 4/3πr³ - 4/3πr³

= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³

= 4 × 3.14 × 9 - 4/3 × 3.14 × 8

= 113.04 - 33.52

= 79.52

If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;

= 79.52 × 3.25

= 258.44 g

Now, if there are 8 spheres in one box, the weight if box will be;

= 258.44 × 8

= 2,067.52 g

_____________________________

Ahh! Finally done with this, if you have any doubt just do ask me :)

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You multiply a number by 3 subtract 6 then add 2 the results is 20 what's the number
e-lub [12.9K]

You multiply a number by 3 subtract 6 then add 2 the results is 20

what's the number​ ?

Let the number = x

multiply a number by 3

so, it becomes 3x

subtract 6 , so, 3x - 6

then add 2

so, 3x - 6 + 2

The result will be 20

So,

3x - 6 + 2 = 20

solve for x

3x - 4 = 20

Add 4 to both sides

3x - 4 + 4 = 20 + 4

3x = 24

Divide both sides by 3

3x/3 = 24/3

So,

x = 8

5 0
1 year ago
Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

So the integral of f(x,y,z)=x^2+y^2+z^2 is

\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

6 0
3 years ago
Consider the following operations on the number 8.82 x 10^-2. Without using a calculator, decide which would give a significantl
Ksenya-84 [330]

Correct question is;

Consider the following operations on the number 8.85 x 10^(-2). Without using a calculator, decide which would give a significantly smaller value than 8.85 x 10^(-2), which would give a significantly larger value, or which would give essentially the same value.

A) 8.85 × 10^(-2) + 6.69 × 10^(5)

B) 8.85 x 10^(-2) - 6.69 x 10^(5)

C) 8.85 x 10^(-2) x 6.69 x 10^(5)

D) 8.85 × 10^(-2) ÷ 6.69 × 10^(5)

Answer:

Option A & B yield essentially the same value.

Option C yields a significantly smaller value

Option D yields a significantly larger value

Step-by-step explanation:

Since given value for the operations is in 10^(-2) indices, then let's convert the operations numbers from 10^(5) indices to 10^(-2).

Thus;

6.69 × 10^(5) = (6.69 × 10^(-7)) × 10^(-2)

Thus;

A) 8.85 × 10^(-2) + 6.69 × 10^(5) is now;

8.85 × 10^(-2) + ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 + (6.69 × 10^(-7))] × 10^(-2)

The 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same

B) 8.85 x 10^(-2) - 6.69 x 10^(5) is now;

8.85 × 10^(-2) - ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 - (6.69 × 10^(-7))] × 10^(-2)

Again the 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same.

C) 8.85 x 10^(-2) x 6.69 x 10^(5) is now;

(8.85 × 10^(-2)) × ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 × (6.69 × 10^(-7))] × 10^(-2)

When we multiply 8.85 by 6.69 × 10^(-7), the value gotten will be way lower than the initial value of 8.85.

Thus,this operation will give a significantly smaller value.

D) (8.85 × 10-2) ÷ (6.69 × 10^5) is now;

(8.85 × 10^(-2)) ÷ ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 ÷ (6.69 × 10^(-7))] × 10^(-2)

When we carry out the operation:

8.85 ÷ (6.69 × 10^(-7)), it is essentially equal to (8.85 × 10^(7))/6.69.

This means that the new value would be significantly larger than the initial value of 8.85.

Thus,this operation yields a significantly larger value.

4 0
3 years ago
27^-2/3<br><br> A. 9<br> B. 1/9<br> C. -1/9<br> D. -9
geniusboy [140]
<span>27^-2/3
= (3^3)^-2/3
= 3^-2
= 1/3^2
= 1/9

answer
</span><span>B. 1/9</span>
5 0
3 years ago
Which two fractions are equivelent to 1 over 4
Serhud [2]

Answer:

2/8 and 3/12

Step-by-step explanation:

You multiply both the numerator and denominator by the same number to get equivalent fractions.

1 x 2

4 x 2

= 2/8

and

1 x 3

4 x 3

= 3/12

8 0
2 years ago
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