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ololo11 [35]
3 years ago
10

50 POINTS 10 QUESTIONS! Solve each quadratic equation using factoring PLEASE HELP!!

Mathematics
2 answers:
Tanzania [10]3 years ago
6 0

Answer:

Quadratic Equation | Factoring

Solve each quadratic equation using factoring.

1) v² + 5v + 6 = 0

doing middle term factorisation

v²+(3+2)v+6=0

v²+3v+2v+6=0

v(v+3)+2(v+3)=0

(v+3)(v+2)=0

either

<u>v=-3</u>

<u>or</u>

<u>v=-2</u>

2) g² - 3g = 4

keeping all terms in one side

g²-3g-4=0

doing middle term factorisation

g²-(4-1)g-4=0

g²-4g+g-4=0

g(g-4)+1(g-4)=0

(g-4)(g+1)=0

either

<u>g=4</u>

<u>or</u>

<u>g=-1</u>

3)w² + 4w = 0

w(w+4)=0

either

<u>w=0</u>

<u>or</u>

<u>w=-4</u>

4) s² - 8s + 12 = 0

doing middle term factorisation

s²-(6+2)+12=0

s²-6s-2s+12=0

s(s-6)-2(s-6)=0

(s-6)(s-2)=0

either

<u>s=6</u>

<u>or</u>

<u>s=2</u>

5) x ²+ 2x - 35 = 0

doing middle term factorisation

x²+(7-5)x-35=0

x²+7x-5x-35=0

x(x+7)-5(x+7)=0

(x+7)(x-5)=0

either

<u>x=-7</u>

<u>or</u>

<u>x=5</u>

6) r(r + 2) = 99

opening bracket

r²+2r=99

keeping all terms in one side

r²+2r-99=0

r²+(11-9)r-99=0

r²+11r-9r-99=0

r(r+11)-9(r+11)=0

(r+11)(r-9)=0

either

<u>r=-11</u>

<u>or</u>

<u>r=9</u>

7)k(k-4)=-3

opening bracket

k²-4k=-3

keeping all terms in one side

k²-4k+3=0

k²-(3+1)k+3=0

k²-3k-k+3=0

k(k-3)-1(k-3)=0

(k-3)(k-1)=0

either

k=3

or

k=1

8)t²+ 3t + 2 = 0

doing middle term factorisation

t²+(2+1)t+2=0

t²+2t+t+2=0

t(t+2)+1(t+2)=0

(t+2)(t+1)=0

either

<u>t</u><u>=</u><u>-</u><u>2</u>

<u>or</u>

<u>t</u><u>=</u><u>-</u><u>1</u>

9)m ^ 2 - 81 = 0

m²=81

doing square root in both side

\sqrt{m²}=\sqrt{9²}

<u>m=±9</u>

<u>either</u>

<u>m</u><u>=</u><u>9</u>

<u>or</u>

<u>m</u><u>=</u><u>-</u><u>9</u>

10) h²- 17h + 70 = 0

doing middle term factorisation

h²-(10+7)h+70=0

h²-10h-7h+70=0

h(h-10)-7(h-10)=0

(h-10)(h-7)=0

either

<u>h</u><u>=</u><u>1</u><u>0</u>

<u>or</u>

<u>h</u><u>=</u><u>7</u>

slava [35]3 years ago
3 0

Answer:

9) m^2 - 81 = 0

solution,

here,

m^2 - 81 = 0

or, m^2 = 81

or, m^2 = 9^2

or, m = 9 ( removing or cutting both square)

Therefore; m =9

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Suppose that a company prints baseball cards. They claim that 30% of the cards feature rookies, 60% feature veterans, and 10% fe
liraira [26]

Answer:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

Step-by-step explanation:

On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

And in order to test it we need to have observed and expected values. On this case we  can calculate the Expected values like this

E_{rookies}=50*0.3=15

E_{veterans}=50*0.6=30

E_{All stars}=50*0.1=5

The observed values are not provided. The statistic on this case is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i) -E_i}{E_i}

And this statistic follows a chi square distribution with k-1 degrees of freedom on this case k=3, since we have 3 groups.

We can calculate the p valu like this:

P(\chi^2 > \chi^2_{calculated})=p_v

And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.

5 0
3 years ago
Dana is riding her bike. She rides 20 miles in 2 hours, 30 miles in 3 hours, and 40 miles in 4 hours. Find the constant of prop
AnnyKZ [126]
10. 20/2 = 10
30/3=10
40/4=10

Y=10x
5 0
3 years ago
Please help me asap!!
agasfer [191]

C) 5; ASA

A <C = <E

S CB = BE

A <B = <B

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Mr. Peter's has 80 sheets of colored paper seven of his students need it for a project. how many sheets are left over?
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3 years ago
Read 2 more answers
I need help to find the measures and equation pls.
siniylev [52]

Answer:

Equation: 7x + 8x = 180

x = 12

∠CBA = 84

∠CFH = 96

Step-by-step explanation:

We can see that ∠CBA = ∠CFE and ∠CBD = ∠CFH.

We know that the sums of two angles on a straight line are going to be equal to 180.

∠CBA = 7x

∠CFH = 8x

To find the value of x, we must do the following:

7x + 8x = 180

15x = 180

15x/15 = 180/15

x = 12

Now we just substitute to find the angle measures:

∠CBA = 7 · 12 = 84

∠ CFH = 8 · 12 = 96

7 0
2 years ago
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