1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kirill [66]
3 years ago
12

What is the probability of rolling a 6 and then rolling a number less than 4

Mathematics
1 answer:
frozen [14]3 years ago
6 0

I believe that the answer should be 5/6

You might be interested in
scores on a college entrance examination are normally distributed with a mean of 500 and a standard deviation of 100% of people
Softa [21]

We have

\mu = 500

\sigma = 100

425 corresponds to a z of

z_1 = \dfrac{425 - 500}{100} = -\dfrac 3 4

575 corresponds to

z_2 = \dfrac{575 - 500}{100} = \dfrac 3 4

So we want the area of the standard Gaussian between -3/4 and 3/4.  

We look up z in the standard normal table, the one that starts with 0 at z=0 and increases.  That's the integral from 0 to z of the standard Gaussian.

For z=0.75 we get p=0.2734. So the probability, which is the integral from -3/4 to 3/4, is double that, 0.5468.

Answer: 55%

3 0
3 years ago
What is<br> 3x-y=9<br> 2x-y=7
svet-max [94.6K]

Answer:

x=2 and y= -3

Step-by-step explanation:

This is a simultaneous equation. To solve this type of equation, there are three methods; substitution, Elimination and Graphical.

But here, we would be using the substitution method.

3x-y=9 Equation 1

2x-y=7. Equation 2

Getting y from equation 2, we have

-y= 7-2x

Multiply both sides by -

y= 2x-7 Equation 3

Substituting y for 2x-7 in equation 1, we have

3x- (2x-7)=9

3x-2x+7=9

x+7=9

x=9-7

x=2

Substituting x as 2 in equation 3

y=2x-7

y= 2(2)-7

y= 4-7

y= -3

5 0
3 years ago
Read 2 more answers
Provide the answer as a decimal​
olga55 [171]

Answer:

0.55

Step-by-step explanation:

The right-hand column of the table gives us the probabilities of the probability function. We know from elementary probability theory that the "probability" of any event(s) happening would be from 0 to 1 inclusive.

The total probability of all events would add up to 1. So, we look at the probabilities given for each even, x, and add them:

0.29 + 0.09 + 0.03 + 0.04 = 0.45

All of these probabilities and the probability at x = 2 (the unknown) would add up to 1, so we can say:

0.45 + probability (x = 2) = 1

Probability at x = 2 = 1 - 0.45 = 0.55

7 0
3 years ago
1. (3x2 + 4x - 12) = (x + 5)<br> Divide using synthetic division
Kitty [74]
If you are solving for x then here’s how:

(3x2 + 4x - 12) = (x + 5)
Remove the x on the left by remove one x from both of the sides.
(3x2 + 3x - 12) = 5
Add 12 onto both sides
(3x2 + 3x) = 17
Multiply
(6 + 3x) = 17
Take away 6 from both sides
3x = 11
Divide by 3 on both sides
x = 3.666 recurring
4 0
3 years ago
What is the value of q?
AnnyKZ [126]
If q represents the line, then I think it's 8.8 (:
5 0
3 years ago
Other questions:
  • A group walked 3/8 mile in 1/5 hour. Which is the groups walking speed in miles per hour
    9·1 answer
  • Which point is the center of the circle?<br> point w<br> point X<br> point y<br> point z
    14·1 answer
  • 3 + 2-(-3)-7=<br> Please add step by step and make sure the answer is correct
    11·2 answers
  • Three salesmen work for the same company, selling the same product. And, although they are all paid on a weekly basis, each sale
    13·1 answer
  • Jessica jogged at a constant rate of 6 miles per hour how many miles will Jessica jog in 3 2/5 hours
    7·2 answers
  • Let u=(5 -12) and c=-3 what is cu?<br> a)39<br> b)-39<br> c)21<br> d)51
    9·2 answers
  • Here is my question.
    9·2 answers
  • Someone help me pls ill give brainlist to the correct one
    11·1 answer
  • Mark all the statements that are true please help
    5·1 answer
  • does anyone know how to do this asap! with a full explanation please !!! thank you have a great day !!​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!