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notsponge [240]
2 years ago
7

ctivity 2: ons: Using the sum and the product of the roots, find the quadratic equation given its roots. Use the space provided

for your solutions and complete the table below.​

Mathematics
1 answer:
irinina [24]2 years ago
4 0

Answer:

The answer is 6765665

Step-by-step explanation:

plz mark me brainliest plz Plz plz Plz plz

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Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below.
garik1379 [7]

Answer:

The 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =9.2 represent the sample mean 1

\bar X_2 =8.8 represent the sample mean 2

n1=27 represent the sample 1 size  

n2=30 represent the sample 2 size  

\sigma_1 =0.3 population standard deviation for sample 1

\sigma_2 =0.1 population standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =9.2-8.8=0.4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that t_{\alpha/2}=1.96  

Now we have everything in order to replace into formula (1):  

0.4-1.96\sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}=0.281  

0.4+1.96\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=0.519  

So on this case the 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

6 0
3 years ago
HELPPPPPPPP I NEED THE ANSWER PLZZZZZZZZZZZ!!!!!!!!!!! the solutions plz
Vesnalui [34]

Answer:

  1. c = -4.5
  2. z = 20
  3. x = -12
  4. a = -4/7

Step-by-step explanation:

A way to do this that will always work is ...

  • eliminate parenthses and collect terms
  • subtract any constants from the left side
  • subtract any variable terms from the right side
  • divide by the coefficient of the variable

1.

  • 8c -11 -6c = -2
  • 2c -11 = -2
  • 2c = 9
  • c = 4.5

2.

  • 3z +4 -2z -9 = 15
  • z -5 = 15
  • z = 20

3.

  • 12 -4x +18 = 36 +4x +18 -6x
  • 30 -4x = 54 -2x
  • -4x = 24 -2x
  • -2x = 24
  • x = -12

4.

  • 36a -9a -5 = 6a -17
  • 27a -5 = 6a -17
  • 27a = 6a -12
  • 21a = -12
  • a = -12/21 = -4/7
6 0
3 years ago
The animal shelter has both male and female Labrador retrievers in yellow, brown, or black. There is and equal number of each ki
Illusion [34]

Answer:

Step-by-step explanation:

There are choices when it comes to color (3). Then there is the choice between a boy dog or a girl dog (2). Multiply the number of colors by the number of genders. (6)

When choosing a dog from random, you can either choose:

Brown/M

Brown/F

Black/M

Black/F

Yellow/M

Yellow/F

(This list is called the Sample Space, a list of all possible outcomes)

Because the text says that all types of dogs are found in even numbers, it would not matter if there was 6, 12, 18, ... amount of dogs.

When looking at this sample space, you can see that the chance of choosing a Yellow/F dog, is 1 in 6.

5 0
2 years ago
Which of the following statements is TRUE about the midline of a trapezoid?
Y_Kistochka [10]

Answer:

C will be the rightful answer

3 0
2 years ago
Hannah read 8 books in 16 months. What was her rate of reading in books per month?
MrRa [10]
Half a book each month!!! have a good day!
6 0
2 years ago
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