All categories

2 years ago

What are the solutions of (x - 3)(2x + 4) = 0

Mathematics

2 answers:

avanturin [10]2 years ago

8 0

Step-by-step explanation:

(x - 3 ) (2x + 4) = 0

Either

x - 3 = 0

Therefore x = 3

Or.,

2x + 4 = 0

2x = - 4

x = - 4 /2

Therefore x = -2

Now the value of x is 3 or - 2.

Hope it will help :)♥

sladkih [1.3K]2 years ago

5 0

Answer:

x = 3 & x = -2

Step-by-step explanation:

(x-3) = 0 so x = 3

(2x+4) = 0 so 2x = -4 x = -2

You might be interested in

The graph of g(x) is a translation of y = 3/x

Crank

Answer:

Step-by-step explanation:

6 0

3 years ago

Which of the following has six faces?

Goryan [66]

Answer:

Step-by-step explanation:

Hexa means six, so a hexahedron is a figure with six faces. Therefore, choice D is the correct answer.

7 0

3 years ago

F(x)=3x-2 Simplify F(2x)-F(x+2)

inysia [295]

Answer:

3x - 6

Step-by-step explanation:

To evaluate f(2x) and f(x + 2) substitute x = 2x and x = x + 2 into f(x)

f(2x) = 3(2x) - 2 = 6x - 2

f(x + 2) = 3(x + 2) - 2 = 3x + 6 - 2 = 3x + 4

Thus

f(2x) - f(x + 2)

= 6x - 2 - (3x + 4)

= 6x - 2 - 3x - 4

= 3x - 6

7 0

3 years ago

1,755 divided 27=

inna [77]

Answer: the answer is 65

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Please help me answer this question

avanturin [10]

By direct substitution and simplification, the trigonometric function z = cos (2 · x + 3 · y) represents a solution of the partial differential equation $\frac{\partial^{2} t}{\partial x^{2}} - \frac{\partial^{2} t}{\partial y^{2}} = 5\cdot z$ .

<h3>How to analyze a differential equation</h3>

Differential equations are expressions that involve derivatives. In this question we must prove that a given expression is a solution of a differential equation, that is, substituting the variables and see if the equivalence is conserved.

If we know that $z = \cos (2\cdot x + 3\cdot y)$ and $\frac{\partial^{2} t}{\partial x^{2}} - \frac{\partial^{2} t}{\partial y^{2}} = 5\cdot z$ , then we conclude that: