Can someone help me with this pls show work

The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1

Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

4 0

3 years ago

A farmer wants to plant peas and carrots on no more than 200 acres of his farm. If x represents the number of acres of peas and

AfilCa [17]

Answer:

Option D.(60, 135)

Step-by-step explanation:

Let

x -----> the number of acres of peas

y ----> the number of acres of carrots

we know that

The inequality that represent the problem is equal to

$x+y\leq 200$

so

<em>Verify each case</em>

case A) (-50,160)

substitute the value of x and the value of y in the inequality and then compare the result

$-50+160\leq 200$

$110\leq 200$ ----> is true

The point is a solution for the inequality, but is not a viable solution because the number of acres can not be a negative number

case B) (80,160)

substitute the value of x and the value of y in the inequality and then compare the result

$80+160\leq 200$

$240\leq 200$ ----> is not true

therefore

The point is not a solution

case C) (75,-200)

substitute the value of x and the value of y in the inequality and then compare the result

$75-200\leq 200$

$-125\leq 200$ ----> is true

The point is a solution for the inequality, but is not a viable solution because the number of acres can not be a negative number

case D) (60,135)

substitute the value of x and the value of y in the inequality and then compare the result

$60+135\leq 200$

$195\leq 200$ ----> is true

therefore

The point is a viable solution

5 0

3 years ago

Read 2 more answers

I need help on this math problem ASAP.

Luda [366]

Answer:

This shape is a rectangle so that means that the angles are 90°. From sum of angles of a triangle, x + 3x + 10 + 90 = 180 which means 4x + 100 = 180 → 4x = 80 → x = 20°.

5 0

3 years ago

Can someone help pls 10 points

igor_vitrenko [27]

Answer:

m=rise over run

so it would be $\frac{2}{5}$