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statuscvo [17]
3 years ago
13

Nada, solo estoy probando xdxd

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
Jajaja xdxd probando
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Lisa took a survey of her classmates' favorite sport and recorded their genders. The results are in the table below:
Igoryamba

Answer:

0.43

17

Step-by-step explanation:

8 0
3 years ago
Make t the subject of the formula <br> P= 3-2t<br> —————<br> 4+t
Rufina [12.5K]

Answer:

t = \frac{3 - 4p}{p + 2}

Step-by-step explanation:

Given

P = \frac{3 - 2t}{4 + t}

Required

Make t the subject

P = \frac{3 - 2t}{4 + t}

Cross Multiply

P * (4 + t) = 3 - 2t

4p + tp = 3 - 2t

Collect Like Terms

tp + 2t = 3 - 4p

Factorize:

t(p+2) = 3 - 4p

Make t the subject

t = \frac{3 - 4p}{p + 2}

5 0
3 years ago
What is the area of a triangle whose sides are 15 cm, 8 cm and 19 cm?<br>​
ludmilkaskok [199]
Is it 2,280
Hope that work
3 0
3 years ago
For 1-2, the cube shown below has an
IrinaVladis [17]
14*14*14=2744cm^3
C. 2744cm^3

7 0
3 years ago
How many solutions does the system of equations have? Pls help :(
goldfiish [28.3K]

Given the system of equations below:

\large{ \begin{cases} y = 2x + 1 \\  - 4x + 2y = 2 \end{cases}}

The first equation is y-isolated so we can substitute in the second equation.

\large{ - 4x + 2(2x + 1) = 2}

Use the distribution property to expand in and simplify.

\large{ - 4x + 4x + 2 =  2} \\  \large{0 + 2 = 2 \longrightarrow 2 = 2}

The another method is to divide the second equation by 2.

\large{ \frac{ - 4x}{2}  +  \frac{2y}{2}  =  \frac{2}{2} } \\  \large{ - 2x + y = 1}

Arrange in the form of y = mx+b.

\large{y = 1 + 2x \longrightarrow y = 2x + 1}

When we finally arrange, compare the equation to the first equation. Both equations are the same which mean that both graphs are also same and intersect each others infinitely.

For more information, when the both sides are equal for equation - the answer would be infinitely many. If both sides aren't equal (0 = 4 for example) - the answer would be none. If the equation can be solved for a variable then it'd be one solution.

Answer

  • Infinitely Many

Hope this helps. Let me know if you have any doubts!

3 0
3 years ago
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