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SSSSS [86.1K]
3 years ago
15

A bag of candy containing 320 pieces is to be divided up into 18 smaller bags for distribution with fourteen left over. How many

pieces will go in each bag?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

17

Step-by-step explanation:

A bag of candy contains 320 pieces

It is to be divided into 18 smaller bags with fourteen left over

Therefore the pieces that will go in each bag after the distributorn can be calculated as follows

= 320/18

= 17 remainder 14

Hence 17 pieces of candy will be in each bags

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Maya express charges 15 dollar for each person and great holiday charges fixed 84dollar and extra 12 dollar for a person. If the
goblinko [34]

Step-by-step explanation:

15 dollar for each

15*70*12

then 84*70

total amount. the above

6 0
3 years ago
Katie is getting her laundry done it cost $2.25 per square foot of flowers added to the yard if she wants 12.4 ft.² of flowers h
7nadin3 [17]

Answer:

Katie needs to pay $27.9.

Step-by-step explanation:

Given;

Cost of per foot = $2.25

Number of  flowers in her yard = 12.4 square foot

We need to find how much she needs to pay.

Solution:

Now we know that;

1\ ft^2 = \$2.25

So for 12.4 ft^2 = Cost for 12.4 ft^2 .

By using Unitary method we get;

Cost for 12.4 ft^2 = 2.25\times12.4= \$27.9

Hence Katie needs to pay $27.9.

5 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
Help!!!!<br>Given log7⁡3≈0.5646 and log7⁡16≈1.4248, evaluate the expressions.​
Alinara [238K]

Answer:

a)  0.356

b)  1.1397

Step-by-step explanation:

a) log₇2

  • log(2) / log(7)
  • 0.356

b) log₇ (¹⁴⁷/₁₆)

  • <u>log (¹⁴⁷/₁₆)</u>

          log (7)

  • 1.1397
6 0
2 years ago
Which angle’s measure is equal to the sum of the meaures of ∠BAC and ∠BCA? ∠CBA ∠CBE ∠DAC ∠BCF
expeople1 [14]
The answer is B or CBE
4 0
3 years ago
Read 2 more answers
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