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SSSSS [86.1K]
3 years ago
15

A bag of candy containing 320 pieces is to be divided up into 18 smaller bags for distribution with fourteen left over. How many

pieces will go in each bag?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

17

Step-by-step explanation:

A bag of candy contains 320 pieces

It is to be divided into 18 smaller bags with fourteen left over

Therefore the pieces that will go in each bag after the distributorn can be calculated as follows

= 320/18

= 17 remainder 14

Hence 17 pieces of candy will be in each bags

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Answer:

the answer is C

Step-by-step explanation:


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3 years ago
An artificial soccer pitch is 91 meters long and 43 meters wide. If the cost of the pitch is AED 20 per square meter. What is th
Novosadov [1.4K]

The Cost of installing the artificial soccer pitch is $5360

A rectangle is a quadrilateral (has four sides and four angles) in which opposite sides are parallel and equal.

The soccer pitch us rectangle in shape. Hence:

Perimeter of soccer pitch = 2(length + width) = 2(91 + 43) = 268 meters

Cost of installing the pitch = $20 per meter * 268 meters = $5360

The Cost of installing the artificial soccer pitch is $5360

Find out more on perimeter at: brainly.com/question/16596982

6 0
2 years ago
A study done recently 3out of 5 results used brand x how many used brand x out of 2000
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6 0
3 years ago
36 x 2 = 9 x blank x​
Angelina_Jolie [31]

Answer:

x = 8

Step-by-step explanation:

36 × 2 = 9 × x

72 = 9x

9x = 72

9x ÷ 9 = 72 ÷ 9

x = 8

3 0
2 years ago
An experimenter conducted a two-tailed hypothesis test on a set of data and obtained a p-value of 0.44. If the experimenter had
Lyrx [107]

Answer:

Correct option is (C).

The possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.

Step-by-step explanation:

The <em>p</em>-value is the probability of acquiring a result as extreme as the observed result, assuming the null hypothesis statement is true.

The <em>p</em> value of a test is:

Left-tailed test: P(TS

Right-tailed test: P(TS>ts) = 1- P(TS.

Here,

TS = Test statistic

ts = computed value of the test statistic.

The two-tailed <em>p</em>-value is: 2P(TS or 2P(TS>ts).

The <em>p</em>-value of the two tailed test is, 0.44.

Compute the <em>p</em>-value for one-tailed test a follows:

  • For a left-tailed test:

            2P(TS

  • For a right-tailed test:

            P(TS>ts) = 1- P(TS

Thus, the possible value of the <em>p</em>-value for a one-tailed test are 0.22 and 0.78.

The correct option is (C).

3 0
3 years ago
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