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3 years ago

HELP MULTIPLE CHOICE

Mathematics

2 answers:

victus00 [196]3 years ago

8 0

Answer:

2(18k+21)-9

6(7+6k)-9

Step-by-step explanation:

aivan3 [116]3 years ago

4 0

Answer:

$6(6k + 7) - 9 \\ = 6(7 + 6k) - 9 \\ 6k + 7 = 7 + 6k(both \: have \: same \: meaning) \\ thank \: you$

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4 years ago

Write the phrase as an algebraic equation: A number m decreased by 9 is 12.

finlep [7]

Answer:

9 - m = 12

Step-by-step explanation:

9 - m = 12

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3 years ago

A hypothesis will be used to test that a population mean equals 10 against the alternative that the population mean is more than

PilotLPTM [1.2K]

Answer:

A) 2.58

B) 1.96

C) 1.65

Step-by-step explanation:

A hypothesis used to test that

$H_o : \mu = 10$

against the alternatives $H1 : \mu$ not equal to 10

if null hypothesis is true, then distribution of test statics follow

$Zo = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}$

for two sided alternatives hypothesis $( H1: \mu \neq 7)$ , then P value is

$P = 2[1- \phi(\left | Zc \right |)]$ (1)

a)significance level $\alpha = 0.01$

from 1 eq we get

$\pi (\left | Zc \right |) = P(Zo$

Therefore $\left | Zc \right | = 2.58$ FROM Z TABLE

B) significance level $\alpha = 0.05$

from 1st equation we get

$\pi (\left | Zc \right |) = P(Zo < \left | Zc \right |) = 1 - \frac{0.05}{2} = 0.975$

Therefore $\left | Zc \right | = 1.96$ FROM Z TABLE

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$\pi (\left | Zc \right |) = P(Zo$

Therefore $\left | Zc \right | = 1.65$ FROM Z TABLE

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

An amount was invested at r% per quarter. What value of r will ensure that accumulated amount at the end of one year is 1.5 time

zalisa [80]

Answer:

25.75 % interest rate

Step-by-step explanation:

Given:

Amount was invested = r% per quarter

Amount invested = P

Rate of interest = r % per quarter

Time (n) = 4 Quarters

Computation:

A = P(1 + r/100)ⁿ

According to question.

⇒ A = P + 1.5P = 2.5P

⇒ 2.5P = P(1 + r/100)⁴

⇒ 2.5 = (1 + r/100)⁴

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⇒ r/100 = 0.2575

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4 years ago