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svet-max [94.6K]
2 years ago
11

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Mathematics
2 answers:
laila [671]2 years ago
5 0

Answer:ok

Step-by-step explanation:i liked and follow make me brainliest

LuckyWell [14K]2 years ago
3 0

Answer:

Thanks you for the question.

Step-by-step explanation:

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Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 22.4 -2.878 \times {\frac{3.8}{\sqrt{19} } , 22.4 +2.878 \times {\frac{3.8}{\sqrt{19} } ]

                                                 = [19.891 , 24.909]

Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
3 years ago
11) A building casts a shadow of 100 feet. The angle of elevation from the end of the shadow to the top of the
svp [43]

Answer:

≈ 27 ft

Step-by-step explanation:

using the tangent ratio in the right triangle formed by the building and the ground.

tan15° = \frac{opposite}{adjacent} = \frac{?}{100} ( multiply both sides by 100 )

100 × tan15° = ? , then

? ≈ 27 ft ( to the nearest whole number )

5 0
1 year ago
Help please on this math problem: The prices of backpacks at a store are 22, 16, 39, 35, 19, 34, 20, and 26. Find the Mean Absol
Ivanshal [37]
Answer: 7.22
(note: this is a result after rounding. The result before rounding was 7.21875)

========================================================

Explanation:

Given Set of Values = {22, 16, 39, 35, 19, 34, 20, 26}

Add up the values: 22+16+39+35+19+34+20+26 = 211
Divide that sum by 8 as there are 8 values: 211/8 = 26.375

The mean is 26.375

Now subtract the mean from each data value. Apply the absolute value to ensure the difference is never negative

|22 - 26.375| = 4.375
|16 - 26.375| = 10.375
|39 - 26.375| = 12.625
|35 - 26.375| = 8.625
|19 - 26.375| = 7.375
|34 - 26.375| = 7.625
|20 - 26.375| = 6.375
|26 - 26.375| = 0.375

Add up those results
4.375+10.375+12.625+8.625+7.375+7.625+6.375+0.375 = 57.75
Then divide by 8 
57.75/8 = 7.21875

The mean absolute deviation of the prices is 7.21875
Rounded to two decimal places, it is 7.22
Since we're talking about money, it makes sense to round to the nearest penny.

4 0
4 years ago
Convert each rational number into its decimal form. 1. 1/3 2. 1/6 3. 1/9
stepladder [879]

Answer:

1. 0.33  2. 0.16  3. o.11

Step-by-step explanation:

5 0
3 years ago
Area rectangle of 9/10 x3/4
4vir4ik [10]

.675 square units is the answer

7 0
3 years ago
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