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NeX [460]
3 years ago
12

Plz help me out (252x181)

Mathematics
1 answer:
skad [1K]3 years ago
5 0

Answer:

45612

Step-by-step explanation:

plz mark brainliest

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What function is shown on the graph ??
galina1969 [7]
The function shown is f(x)= -1/2 cos(x).

sin(x) makes the line way more “curverier” So both sin(x) functions are out. It is NOT 1/2 cos(x) because it would make the y-intercept 0, not .5 In the picture it’s starting at .5 so it’s f(x)=-1/2 cos(x)
4 0
4 years ago
Solve.<br><br> 6 divided by 2(1 + 2) =<br><br> Ok goodluck please tell me the answer :)
dalvyx [7]

Answer:

9

Step-by-step explanation:

Based on the order of operations, this would be 3 times 3, which is 9 I think.

4 0
3 years ago
Read 2 more answers
What is the equation of the circle with center (1, -1) that passes through the point (5, 7)?
Inessa [10]

Answer:

Equation of the circle =

80 = ( x - 1)^2 + (y + 1)^2

Step-by-step explanation:

Center = (1 , -1)

Point = ( 5 , 7)

Eqn of a circle is

r^2 = (x - h)^2 + (y - k)^2

We are not given the radius of the circle, fortunately we are provided the information that the circle contains a point ( 5, 7), so we use the above information to find r

Using the center (1, -1)

h - 1

k - -1

r^2 = (x - 1)^2 + ( y - -1)^2

r^2 = (x - 1)^2 + (y + 1)^2

With the point ( 5,7)

x = 5

y = 7

r^2 = ( 5 - 1)^2 + ( 7 + 1)^2

= 4^2 + 8^2

= 16 + 64

= 80

r^2 = 80

r = square root of 80

r = 8.94

The r = 8.94 , which means the equation of the circle is

80 = (x - 1)^2 + ( y + 1)^2

5 0
3 years ago
Sara is trying to find an equation for a line that passes through (5, 2) and is perpendicular to 3x + 2y = 15. Explain the steps
Anettt [7]
Not on your list, but an easy way is
.. a) swap coefficients of x and y, negating one. (Now you have 2x -3y.)
.. b) set any constant term to zero (now you have 2x -3y = 0)
.. c) translate the line to the point (5, 2) by substituting x ⇒ x-5, y⇒ y-2
2(x -5) -3(y -2) = 0


The way you've been taught, selection C is the proper choice.

7 0
3 years ago
What is the LCD of 1/6 and 5/12 and 11/18
Oksi-84 [34.3K]
Finding the Lowest Common Denominator of: \frac{1}{6} ;  \frac{5}{12} ;  \frac{11}{18} &#10;

Here's to find out how it was our LCD:  \frac{1}{6} =  \frac{6}{36}
                                                          \frac{5}{12} =  \frac{15}{36}
                                                           \frac{11}{16} =  \frac{22}{36}
To  find the fraction on the right side we had to multiply (and somewhat divide to get the answer)

So, therefore the Lowest Common Denominator of this question would most likely be: 36

Good Luck! 
5 0
3 years ago
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