Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
364.5 because 9 to the third power is 729. 729 divided by 2 is 364.5
Answer:
Letter A.
Step-by-step explanation:
0 is not divisible, so the last the last two alternatives are impossible.
The second one doesn't work, so I'd stick to letter A.
