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3 years ago

Who invented the word "book?"

Mathematics

1 answer:

jarptica [38.1K]3 years ago

7 0

Wow!!thats a word from the old english that made it

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Alex Ar [27]

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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3 years ago

The table shows Ava's checking account activity for several weeks. Ava's beginning balance was $685. What was her ending balance

Dafna11 [192]

B. Deposit means she added money to her account so you would add 175 and 180 to 685 (giving you 1040). Withdrawal means she took money out of her account so you would subtract 240, 140, and 350 from 1040 giving you your answer of $310 :)

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3 years ago

Which is the area of the rectangle? 69 115 100

Burka [1]

Answer:

Step-by-step explanation:

3 0

3 years ago

Prove that the following four points will form a rectangle when connected in order

Lemur [1.5K]

Answer:

Step-by-step explanation:

If the diagonals of the rectangle are congruent,

AC = BD

By using formula to calculate the distance between two points,

Distance between two points = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(0, -3) and C(2, 8),

AC = $\sqrt{(8+3)^2+(2-0)^2}$

= $\sqrt{125}$

= $5\sqrt{5}$

Similarly, distance between two points B(-4, 0) and D(6, 5),

BD = $\sqrt{(5-0)^2+(6+4)^2}$

= $\sqrt{125}$

= $5\sqrt{5}$

Therefore, both the diagonals are congruent.

Hence, given quadrilateral ABCD is a rectangle.

8 0

3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago