Hey there! In this problem, the solutions, both real and imaginary are provided. We have to work backwards to create a polynomial function which matches these solutions:
f(x) = (x - 6), (x + [5 + 2i]), (x + [5 - 2i])
Create a difference of squares,
f(x) = (x - 6), ([x + 5] + 2i), ([x + 5] - 2i)
f(x) = (x - 6), ([x + 5]^2 + 4)
[(x + 5)(x + 5)] + 4
x^2 + 5x + 5x + 25 + 4
x^2 + 10x + 29
f(x) = (x-6), (x^2 + 10x + 29)
f(x) = x^3 + 10x^2 + 29x - 6x^2 - 60x - 174
Combine like terms,
f(x) = x^3 + 4x^2 + 29x - 174
There we have our answer, a polynomial of degree 3.
Answer:
There was 62.23% change in radius as the ion formed.
Step-by-step explanation:
Given
Radius of Aluminium atom = 143 pm
Radius of Aluminium atom = 54 pm
Change is the radius = Radius of Aluminium atom - Radius of Aluminium
atom = 143 -54 = 89
Now to find % Change is the radius we will divide Change is the radius by Radius of Aluminium atom and multiply by 100 we get
% Change is the radius =
Hence there was 62.23% change in radius as the ion formed.
Answer:
7.9km
Step-by-step explanation:
(a)See attached for the diagram representing this situation.
(b)
In Triangle ABC
Next, we determine the value of Angle B.
Finally, we find b.
The distance between the small plane and the observation tower is 7.9km.
