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Verizon [17]
4 years ago
5

15 POINTS!!!!! !!!!!! could i have some help on #39 with an explanation?? i just really don’t get it, lol. i thought i did, but

then i looked at the answer key, and it is NOT what i thought. thank you guys so much, and happy halloween!!

Mathematics
1 answer:
wolverine [178]4 years ago
8 0

Hey there! In this problem, the solutions, both real and imaginary are provided. We have to work backwards to create a polynomial function which matches these solutions:

f(x) = (x - 6), (x + [5 + 2i]), (x + [5 - 2i])


Create a difference of squares,

f(x) = (x - 6), ([x + 5] + 2i), ([x + 5] - 2i)

f(x) = (x - 6), ([x + 5]^2 + 4)


[(x + 5)(x + 5)] + 4

x^2 + 5x + 5x + 25 + 4

x^2 + 10x + 29


f(x) = (x-6), (x^2 + 10x + 29)

f(x) = x^3 + 10x^2 + 29x - 6x^2 - 60x - 174

Combine like terms,

f(x) = x^3 + 4x^2 + 29x - 174


There we have our answer, a polynomial of degree 3.

f(x) = x^3 + 4x^2 + 29x - 174

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