Answer:
36
Step-by-step explanation:
Use pythagorean theorem
side 1 = 9
side 2 = 12
9^2 + 12^2 = third side ^2
third side = 15
9+12+15 = 36
Hope this helpful!!!!! :)
Answer:
Option 3 is correct that is ![(6+s)(s^2-6s+36)](https://tex.z-dn.net/?f=%286%2Bs%29%28s%5E2-6s%2B36%29)
Step-by-step explanation:
We have general formula for sum of cube which is
![a^3+b^3=(a+b)(a^2+b^2-ab)](https://tex.z-dn.net/?f=a%5E3%2Bb%5E3%3D%28a%2Bb%29%28a%5E2%2Bb%5E2-ab%29)
Here, we have a=s and b=6
on substituting the values in the formula we will get
![6^3+s^3=(6+s)(s^2+6^2-6s)](https://tex.z-dn.net/?f=6%5E3%2Bs%5E3%3D%286%2Bs%29%28s%5E2%2B6%5E2-6s%29)
After simplification we will get
![6^3+s^3=(6+s)(s^2+36-6s)](https://tex.z-dn.net/?f=6%5E3%2Bs%5E3%3D%286%2Bs%29%28s%5E2%2B36-6s%29)
After rearranging the terms we will get
which exactly matches option 3 in the given options.
Therefore, option 3 is correct that is ![(6+s)(s^2-6s+36)](https://tex.z-dn.net/?f=%286%2Bs%29%28s%5E2-6s%2B36%29)
7,999,998 is the number you are looking for