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k0ka [10]
3 years ago
9

Help me please ........

Chemistry
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

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Based on the Lewis/electron dot representation
blsea [12.9K]

Answer:

A. 1:3

Explanation:

If we look at the ions shown in the image attached to the question, we will notice that we have aluminum (Al^3+), a trivalent ion combining with the iodide ion (I^-).

Aluminum can easily give out its three outermost electrons to three atoms of iodine. If aluminum gives out its three electrons, it achieves the stable octet structure. Iodine atoms have seven electrons in their outermost shell. They only need one more electrons to complete their octet. This one electron can be gotten by the combination of three iodine atoms with one atom of aluminum. One electron each is transferred from the aluminum atom to each iodine atom to form AlI3 with a ratio of 1:3.

7 0
3 years ago
What is the SI unit for the mass of subatomic particles?
gogolik [260]

<em>hey, im jordan :)</em>

the SI unit for the mass of subatomic particles is <u>amu (atomic mass unit)</u>

<em>hope this helps!</em>

<em>have a great day :D</em>

4 0
3 years ago
Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m
faust18 [17]

Answer:

56°

Explanation:

First calculate a:

a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}

The interplanar spacing can be calculated from:

d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}

The diffraction angle is determined from:

\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476

Solve for \theta

\theta=\sin ^{-1}(0.476)=28^{\circ}

The diffraction angle is:

2 \theta=2\left(28^{\circ}\right)=56^{\circ}

4 0
3 years ago
PLEASE HELP &lt;3
frutty [35]
In order for carbon to be stable and have 8 electrons, it must make 4 total covalent bonds.

In prefer for oxygen to be stable and have 8 electrons, it must make 2 covalent bonds.

So, we can deduce that CO2 looks like this:

O=C=O

This molecule has two double bonds.

Pssst...Can I get a brainliest?
8 0
3 years ago
a sample of ammonia contains 9g hydrogen and 42g nitrogen. another sample contains 5g hydrogen .calculate the amount of nitrogen
balandron [24]
9 g of hydrogen - 42 g of nitrogen
5 g of hydrogen - x g of nitrogen

9x=42 \cdot 5 \\&#10;9x=210 \\&#10;x \approx 23.33

The mass of nitrogen in the second sample is 23.33 g.
4 0
3 years ago
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