Theoretical yield is defined as the total amount of product formed for given reactants in a chemical reaction. It is an ideal case which assumes no exceptions or wastage.

The mathematical relation between the actual yield, percent yield and theoretical yield is as follows -

$P.Y. = \frac{M_{A.Y.}}{M_{T.Y.}} * 100$

Where

P.Y. represents the percent yield a

M A.Y. represents the mass obtained from actual yield

M T.Y. represents the mass obtained from theoretical yield

Hence, if we rearrange the formula, we get -

$M_{T.Y.} = \frac{M_{A.Y.}}{P.Y.} * 100$

Hence, option C is correct

5 0

3 years ago

PLEASE HELP 20 points

777dan777 [17]

n = 1.5atm (15L) / .0821 (280k) = .98 mol NaCl

NaCl = 22.99g Na + 35.45g Cl = 58.44g NaCl

58.44g NaCl x .98 mol NaCl = 57.27g NaCl

Explanation:

hope you get it right :)

4 0

3 years ago

A stock solution containing Mn2 ions was prepared by dissolving 1.269 g pure manganese metal in nitric acid and diluting to a fi

SOVA2 [1]

Answer:

Explanation:

Hope this helpssss

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8 0

3 years ago