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3 years ago

Write an equivalent fraction for each whole number

1 answer:

3 0

The equivalent of a whole number is
you just need to multiply your whole number with a number, the numerator is the answer that you just multiply, the denominator is the number you just choose to multiply.
Ex: Whole number given: 2, find an equivalent fraction:
Chose number: 5, 2*5=10
So 10 is your numerator and 5 is your denominator, and when you divide them you get 2. Hoped I helped:)

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Which term of the AP 21, 18, 15 ...... is -81 ?

amid [387]

Given AP is 21 ,18,15,...

First term = 21

Common difference = 18-21 = -3

Let an = -81

We know that

an = a+(n-1)d

⇛21+(n-1)(-3) = -81

⇛ 21-3n+3 = -81

⇛24-3n = -81

⇛ 24+81 = 3n

⇛ 105= 3n

⇛ n = 105/3

⇛ n = 35

35th term of the AP is -81.

also read similar questions: Which term of a AP 5 , 13 , 21 ,... is 181?

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Which term of the AP:3, 8, 13, 18,...,is 78?

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3 0

3 years ago

Solve using quadratic formula Show work/explain X^2 - 2x - 24 = 0

iVinArrow [24]

Answer:

x = 6 , − 4

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

3 years ago

Sydney wrote the equation y+1=12(x−3). y + 1 = 1 2 ( x − 3 ) . Explain her error and then write the correct equation in point-sl

yanalaym [24]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given equation:

$\to y + 1 = 12 ( x - 3 )$