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2 years ago

Solve for the value of k.

Mathematics

2 answers:

OLEGan [10]2 years ago

7 0

Answer:

The value of K is 5

Step-by-step explanation:

I reversed it.

The tiny squares means 90⁰, so 90+49=139

All of these angles add up to 180⁰

So 180-139=41

The k equation equals 41⁰, so reverse it to find answer

41-1=40

40÷8=5

olga_2 [115]2 years ago

4 0

I’m not going home but I’ll call later tonight or later bye to my dad and I see if y’all I need

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Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Jus

vichka [17]

Answer:

(25.732,30.868)

Step-by-step explanation:

Given that in a random sample of 42 people, the mean body mass index (BMI) was 28.3 and the standard deviation was 6.09.

Since only sample std deviation is known we can use only t distribution

Std error = $\frac{s}{\sqrt{n} } =\frac{6.09}{\sqrt{42} } \\=0.9397$

$df = 42-1 =41$

t critical for 99% two tailed $= 2.733$

Margin of error $= 2.733*0.9397=2.568$

Confidence interval lower bound = $28.3-2.568=25.732$

Upper bound = $28.3+2.568=30.868$

3 0

2 years ago

If a scalene triangle has its measures 4 m, 11 m and 8 m, find the largest angle.

soldier1979 [14.2K]

Answer:

129.8 approximately

Step-by-step explanation:

So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.

So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.

My math is case sensitive.

X is the angle opposite to the side x.

Law of cosines formula is:

$x^2=a^2+b^2-2ab \cos(X)$

So we are looking for X.

We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).

$11^2=4^2+8^2-2(4)(8)\cos(X)$

$121=16+64-64\cos(X)$

$121=80-64\cos(X)$

Subtract 80 on both sides:

$121-80=-64\cos(X)$

$41=-64\cos(X)$

Divide both sides by -64:

$\frac{41}{-64}=\cos(X)$

Now do the inverse of cosine of both sides or just arccos( )

[these are same thing]

$\arccos(\frac{-41}{64})=X$

Time for the calculator:

X=129.8 approximately

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3 years ago

Suppose the wholesale price of a certain brand of medium-sized eggs p (in dollars/carton) is related to the weekly supply x (in

Mrrafil [7]

Answer:

1300

Step-by-step explanation:

We are given

x = 35

$\frac{dp}{dt}=-0.05$ [rate of change of price with time]

We want to find $\frac{dx}{dt}$ , which is the rate at which supply is changing.

First, we need to implicitly differentiate the equation given:

$625p^2-x^2=100\\1250p\frac{dp}{dt}-2x\frac{dx}{dt}=0$

Here, we have what we need except for p. We find p when x = 35:

$625p^2 - x^2 =100\\625p^2 - (35)^2 =100\\625p^2=1325\\p=1.46$

Now, find dx/dt:

$1250(1.46)(-0.05)-2(35)\frac{dx}{dt}=0\\-91.25-70\frac{dx}{dt}=0\\\frac{dx}{dt}=-1.30$

In thousands, 1.30 * 1000 = 1300 cartons per week decrease

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3 years ago

Tell me the ordered pair for the y-intercept.

Leno4ka [110]

(0 , 3) is the ordered pair

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2 years ago

What is the range of y = sin θ ?

Eva8 [605]

[-1,1] if you want interval notation but its just between negative one and 1

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2 years ago