21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000
After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers. Find the LCM of these sets of numbers. Multiply each factor the greatest number of times it occurs in any of the numbers. 9 has two 3's, and 21 has one 7, so we multiply 3 two times, and 7 once.
Answer:
$12
Step-by-step explanation:
3 cars divide that by $18 and u get $6 per car. multiply that by two cars nd you get $12.
Answer: x = 23 and y = 13
Explanation:
let x and y be the two number.
Where:
(x + y)/2 = 18 => x + y = 18 x 2 = 36
and:
x - y = 10
Thus we get:
x + y = 36 (1)
x - y = 10 (2)
Add (1) and (2):
x + y + x - y = 36 + 10
2x = 46
x = 23
If x = 23
then x - y = 10
23 - y = 10
-y = -13
y = 13
