Well plug 0 in for x and solve for y and that is the vertex of your expression
Answer:
1/26
Step-by-step explanation:
Answer:
Algebra Examples
Popular Problems Algebra Find the Axis of Symmetry f(x)=x^2-5 f(x)=x2−5 Set the polynomial equal to y to find the properties of the parabola. y=x2−5
Rewrite the equation in vertex form.
y=(x+0)2−5 Use the vertex form, y=a(x−h)2+k, to determine the values of a, h, and k.a=1h=0k=−5
Since the value of a is positive, the parabola opens up.
Opens Up
Find the vertex
(h,k).(0,−5)
Find p, the distance from the vertex to the focus.
14 Find the focus.
(0,−194)
Find the axis of symmetry by finding the line that passes through the vertex and the focus.
x=0
Letter C
Use the Distance formula
sq rt [ (x2 - x1)^2 + (y2 - y1)^2 ]
sq rt [ (10-5)^2 + (2 - 4)^2 ]
sq rt [ (5)^2 + (-2)^2 ]
sq rt ( 25 + 4)
Square root of 29
A = l x w
225 = l * 13 3/4
225 ÷ 13 3/4 = l * 13 3/4÷ 13 3/4
16 4/11 = l
Length = 16 4/11 inches
