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3 years ago

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Please help me I

id="TexFormula1" title=" {x}^{2} - {y}^{2} + 4y - 4" alt=" {x}^{2} - {y}^{2} + 4y - 4" align="absmiddle" class="latex-formula">

2 answers:

maksim [4K]3 years ago

6 0

Answer:

hope it's was helpful to you

Ivenika [448]3 years ago

4 0

Answer:

${x}^{2} - {y}^{2} + 4y - 4 \\ \\ {x}^{2} - ( {y}^{2} .2.y.y + {2}^{2} ) \\ \\ {x}^{2} - (y - 2) {}^{2} \\ \\ (x + y - 2)(x - y + 2)$

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3 years ago

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Answer:

$\hat p = \frac{0.244+0.326}{2}=0.285$

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Step-by-step explanation:

For this case we have a confidence interval given as a percent:

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We know that the confidence interval for the true proportion is given by:

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And thats equivalent to:

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And the margin of error can be estimaed using the fact that the confidence interval is symmetrical

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And then the confidence interval in the form desired is:

$0.285 \pm 0.041$

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3 years ago

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Answer:

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Answer:

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