Question

This exercise provides information about data in a survey of students,

Answer 1

The probability of the proportion who are females is "0.5186".

Given values are:

In a survey,

• Number of females, $n_1 = 181$
• Number of males, $n_2=168$

The Probability will be:

→ $P(Female) = \frac{n_1}{n_1+n_2}$

By substituting the values, we get

→                    $= \frac{181}{181+168}$

→                    $= \frac{181}{349}$

→                    $= 0.5186$

Learn more about Probability here:

brainly.com/question/17094091