Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Step-by-step explanation:
1/5x+60=2/3x-2
subtract 1/5x from 2/3x
when you do that you should get 0.46x repeating
then you add two to 60
you should get 62
62=0.46x
divide x
you get 134.7
Answer:
5ab - 8a - 5b - 8
Step-by-step explanation:
each of these can be divided by 5
7=2x + 15 2x= -8 x= -4
<span>8= 3x 8= 3x+0 3x +-8 3(-4) +-8 -12 - 8 </span>
<span>Final Answer -20</span>
