Answer:
t^2 - 11t + 14
Step-by-step explanation:
Begin by grouping like terms in 9t^2+14-17t+6t-8t^2.
First we have 9t^2 - 8t^2, or 1t^2.
Next, we have -17t + 6t, or -11t.
Last, we have the constant term 14.
The expression in simplified form is t^2 - 11t + 14.
Answer:
y = 6 + 4x
After 4 years, the tree would be 22 ft tall.
Step-by-step explanation:
Hi there!
Let x = the number of years that pass
Let y = the height of the tree (ft)
We're given that the 6-foot tree grows at a rate of 4 ft per year. This means that the height of the tree will be equal to 6 ft, the original height, plus another 4 ft every year that passes.
Height of tree = 6 feet + 4 feet × number of years that pass
y = 6 + 4x
To solve for how tall the tree would be 4 years after Dina plants it, replace x with 4, since 4 years have passed:
y = 6 + 4(4)
y = 6 + 16
y = 22
Therefore, the tree would be 22 ft tall.
I hope this helps!
Hello,
Angles y and 3y+8 are supplementaries since the quadrilater is inscribed
y+3y+8=180
==>4y=172
==>y=43 (°)
two thousand ten and eight tenths
Perpendicular lines, slope is opposite and reciprocal
so slope of new line = - 4
passes through (-2, -6) in point-slope form
y + 6 = -4(x + 2)
Answer is C. y + 6 = -4 (x + 2)
