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3 years ago

If it takes 7 vehicles to transport 42 people how many vehicles will it take ro transport 132 people

Mathematics

2 answers:

Ivahew [28]3 years ago

6 0

It will take 22 vehicles to transport 132 people

victus00 [196]3 years ago

4 0

Hey there!

Here is your answer:

The proper answer to this question is "21 vehicles".

Reason:

Just divide 132 by 42 and that amount is how many cars you need to transport that amount!

132÷42=3.14285714

Now add 42 intill is gets to the amount of 132!

42+42+42=126

7+7+7=21

Therefore you would need 21 vehicles to transport 132 people!

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

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sdas [7]

Answer:

-14

Step-by-step explanation:

if n = 1.5, replace all letters labeled "n" with 1.5

5(1.5) - (20 +1.5)

5 x 1.5 = 7.5

(20+1.5) = 21.5

7.5 - 21.5 = -14

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3 years ago

Read 2 more answers

Which pair of equations represent PARALLEL lines? A) y=2x and y = -1/2x B) y=2x and y = -1/2 C) y=2 and y=-2 D)y=2x=-2

Gennadij [26K]

Answer:

None

Step-by-step explanation:

Step 1: Write all the equations in the form y=mx+c, where m represents the gradient.

Notably, the equations are in that form already.

Step 2: Compare which equation have same value of m

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3 years ago

What is the Product of x-3 and x-9

Serggg [28]

Answer:

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Step-by-step explanation:

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3 years ago

Jollibee employs a total of 10 cashiers and 15 kitchen crews. The manager selects a team of 2 cashiers and

Airida [17]

Answer:

The manager can select a team in 61425 ways.

Step-by-step explanation:

The order in which the cashiers and the kitchen crews are selected is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In how many ways can the manager select a team?

2 cashiers from a set of 10.

4 kitchen crews from a set of 15. So

$T = C_{10,2}*C_{15,4} = \frac{10!}{2!(10-2)!}*\frac{15!}{4!(15-4)!} = 45*1365 = 61425$

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3 years ago

There is an inverse relationship between x and y. If y is when x is 3, what is x when y is 9?

maria [59]

For example, y = k/x; when x = 3 => k = 3y; when y = 9 => k = 27 and x = 27/9 = 3;
The answer is 3!

3 0

3 years ago