To find the distance b/t 2 points you need to use the distance formula. that is
distance = square root of (x2-x1)^2 + (y2-y1)^2
to fill it in, it is
(it doesnt matter which point you start with, as long as its consistent)
x1 = 9
x2 = 5
y1 = -8
y2 = -10
square root of (5-9)^2 + (-10-8)^2
lets do algebra!
square root of (-4)^2 + (-18)^2
square root of 16 + 324
square root of 340
Distance = 18.4391 units.
I hope this helps!
Answer:
area = 277 units²
Step-by-step explanation:
area = (25 x 5) + (8 x 13) + (8 x 6) = 277 units²
I’ve never done a tape diagram before (so this might be wrong). But I think it’s:
6t=9
If this is correct, I hope it helps :)
Perimeter of rectangle = length + length + width + width
To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14
Rectangle with perimeter 12
Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3
Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have
Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have
The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12
length = 4 and width = 2
length = 5 and width = 1
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Rectangle with perimeter of 14
Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14
Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14
Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14
We can have 3 different combinations of length and width
