Question

Point P'P′P, prime is the image of P(6,0)P(6,0)P, left parenthesis, 6, comma, 0, right parenthesis under the translation (x,y)\to(x-6,y-1)(x,y)→(x−6,y−1)left parenthesis, x, comma, y, right parenthesis, \to, left parenthesis, x, minus, 6, comma, y, minus, 1, right parenthesis.

Answer 1

The location of point P is at (0, -1)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

Translation is the movement of a point left, right, up or down in the coordinate plane.

We are given the coordinates of point P and asked to find the coordinates of the image P'.

Given point P at P(6, 0), A translation of (x,y)→(x−6,y−1) is done to produce an image P'. Therefore point P is translated 6 units left and 1 unit down to get P'.

Hence P' = (0, -1)

Therefore P' is at (0, -1)

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