Answer:
4
lolz sorry for a late answer bud
Step-by-step explanation:
Answer:
option f is right
Step-by-step explanation:
Given that data is collected to perform the following hypothesis test.

(right tailed test)
Sample mean = 5.4
p value = 0.1034
when p value = 0.1034 we normally accept null hypothesis. i.e chances of null hypothesis true is the probability of obtaining test results at least as extreme as the results actually observed during the test, assuming that the null hypothesis is correct
f) If the mean µ does not differ significantly from 5.5 (that is, if the null hypothesis is true), then the probability of obtaining a sample mean y as far or farther from 5.5 than 5.4 is .1034.
.
Answer:
- <em>0.75</em><em> liters of 5% hydrochloric acid solution </em>
- <em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>
Step-by-step explanation:
Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.
As Rajan need total of 1 liter of solution, so
i.e
--------------------1
As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

i.e
-------------2
Putting value of x from equation 1 in equation 2,





Putting the value of y in equation 1,

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters of 45% hydrochloric acid solution.